Answer:
The answer is "Screen B is wider , because 5.3 is greater than 5 and one-third".
Step-by-step explanation:
The mobile display unit must be made similar. Phone A uses a decimal device, and telephone B uses a fraction in this case.
It's easier for you to use. Attempt using the decimal. The width of the phone B fraction could then be translated to decimal width. The computing is:
= 5 cm + 
cm
= 5 cm + 0.333cm
= 5.333 cm
It is evident from here that the wider screen of Phone B is than that of Phone A.
This is a very long question. I'm not going to write all of it out but I will give you a starting point. Find your x by making y in the formula equal to 0.
2x + 3y = 1470
2x + 3(0) = 1470
2x = 1470
x = 735
Your furthest point on the x axis is (735,0).
Do the same for y.
2x + 3y = 1470.
2(0) + 3y = 1470
3y= 1470
y= 490
Your highest point is (0,490).
Now that both are plotted, draw a straight line connecting the two points. There's your graph.
Check
Answer:
The wedge cut from the first octant ⟹ z ≥ 0 and y ≥ 0 ⟹ 12−3y^2 ≥ 0 ⟹ 0 ≤ y ≤ 2
0 ≤ y ≤ 2 and x = 2-y ⟹ 0 ≤ x ≤ 2
V = ∫∫∫ dzdydx
dz has changed from zero to 12−3y^2
dy has changed from zero to 2-x
dx has changed from zero to 2
V = ∫∫∫ dzdydx = ∫∫ (12−3y^2) dydx = ∫ 12(2-x)-(2-x)^3 dx =
24(2)-6(2)^2+(2-2)^4/4 -(2-0)^4/4 = 20
Step-by-step explanation:
Answer:
A: -2
Step-by-step explanation:
You want some factor k such that k(5x) +(10x) = 0. That is, 5k+10 = 0. The solution to this is k=-2, corresponding to selection A.
