Answer:

Step-by-step explanation:
The formula of a midpoint between two points A(x₁, y₁) and B(x₂, y₂):

We have the points (3, 17) and (-14, -8).
Substitute:

Answer:
80 cm²
Step-by-step explanation:
Trapezoid LPKB has area ...
A = (1/2)(b1 +b2)h = (1/2)(4 +20)(20) = 240 . . . . cm²
Triangle BPN has area ...
A = (1/2)bh = (1/2)(20)(20) = 200 . . . . cm²
Triangle BKN has a height that is 4/5 the height of triangle BPN, so will have 4/5 the area:
ΔBKN = (4/5)(200 cm²) = 160 cm²
The area of quadrilateral LPKB is that of trapezoid LPNB less the area of triangle BKN, so is ...
240 cm² - 160 cm² = 80 cm²
Answer:
35.7 km and 248.3 °
Step-by-step explanation:
I will attach the diagram to an image to make it easier to understand.
We will use the formula corresponding to the law of cosine
y² = 42² + 28² - (2 * 42 * 25 * cos 58 °)
y² = 2389 - 1112.83 = 1276.17
y = √1276.17
y = 35.72 km
Now, to calculate the surveyor's bearing from her base camp we must use the sine law:
[(Sin 58 °) / y] = [(Sin A) / 42]
Without A = (42 * without 58 °) /35.72
A = sin⁻¹ (0.9971)
A = 85.7 °
Bearing of the surveyor from the base camp = 270 ° - (85.7 ° - 64 °) = 248.3 °