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11Alexandr11 [23.1K]
2 years ago
8

A fourth-grade teacher gives homework every night in both mathematics and language arts. the time to complete the mathematics ho

mework has a mean of 10 minutes and a standard deviation of 3 minutes. the time to complete the language arts assignment has a mean of 12 minutes and a standard deviation of 4 minutes. assuming the times to complete homework assignments in math and language arts are independent, the standard deviation of the time required to complete the entire homework assignment is
Mathematics
2 answers:
xz_007 [3.2K]2 years ago
7 0
The standard deviation for the combined assignment is 5 minutes.

To combine the standard deviations, we use:

\sigma_z=\sqrt{(\sigma_x)^2+(\sigma_y)^2}

With our information, we have:
\sigma_z=\sqrt{3^2+4^2}
\\
\\=\sqrt{9+16}=\sqrt{25}=5
slega [8]2 years ago
7 0

Answer:

5 min

Step-by-step explanation:

The combine standard deviation, SDf, of two independent variables having standard deviation, SD1 and SD2, is given by:

SDf² = SD1² + SD2²

SDf²= 3² + 4²

SDf= 5

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Find the midpoint of the segment between the points (3,17) and (−14,−8)
mixas84 [53]

Answer:

\large\boxed{\left(-\dfrac{11}{2},\ \dfrac{9}{2}\right)}

Step-by-step explanation:

The formula of a midpoint between two points A(x₁, y₁) and B(x₂, y₂):

M_{AB}\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

We have the points (3, 17) and (-14, -8).

Substitute:

M(x,\ y)\\\\x=\dfrac{3+(-14)}{2}=\dfrac{-11}{2}\\\\y=\dfrac{17+(-8)}{2}=\dfrac{9}{2}

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2 years ago
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What is the y-intercept of the function y = negative one-half cosine (three-halves x)?
Jet001 [13]
A. Sorry if I’m wrong
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2 years ago
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Given: LMNB is a square, LM = 20cm, P∈ LM , K ∈ PN , PK = 1 5 PN, LP = 4 cm Find: Area of LPKB
Bad White [126]

Answer:

  80 cm²

Step-by-step explanation:

Trapezoid LPKB has area ...

  A = (1/2)(b1 +b2)h = (1/2)(4 +20)(20) = 240 . . . . cm²

Triangle BPN has area ...

  A = (1/2)bh = (1/2)(20)(20) = 200 . . . . cm²

Triangle BKN has a height that is 4/5 the height of triangle BPN, so will have 4/5 the area:

  ΔBKN = (4/5)(200 cm²) = 160 cm²

The area of quadrilateral LPKB is that of trapezoid LPNB less the area of triangle BKN, so is ...

  240 cm² - 160 cm² = 80 cm²

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2 years ago
Adult panda weights are normally distributed with a mean of 200 pounds and a standard deviation of 50 pounds. The largest pandas
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Answer:

16%

Step-by-step explanation:

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A surveyor leaves her base camp and drives 42km on a bearing of 32 degrees. She then drives 25km on a bearing of 154 degrees. Ho
Eva8 [605]

Answer:

35.7 km and 248.3 °

Step-by-step explanation:

I will attach the diagram to an image to make it easier to understand.

We will use the formula corresponding to the law of cosine

y² = 42² + 28² - (2 * 42 * 25 * cos 58 °)

y² = 2389 - 1112.83 = 1276.17

y = √1276.17

y = 35.72 km

Now, to calculate the surveyor's bearing from her base camp we must use the sine law:

[(Sin 58 °) / y] = [(Sin A) / 42]

Without A = (42 * without 58 °) /35.72

A = sin⁻¹ (0.9971)

A = 85.7 °

Bearing of the surveyor from the base camp = 270 ° - (85.7 ° - 64 °) = 248.3 °

4 0
2 years ago
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