<span>I would measure the mass of the solid substance. I would prepare a known mass of room temperature water large enough to submerge the solid substance in question. I would place the water in an insulated container. Then I would heat the solid substance to a known temperature. I would measure the temperature of the heated sample and the water. Then I would submerge the sample in the water and allow the sample and the water to reach the same temperature. I would measure this equilibrium temperature.
I would interpret the difference in temperature between the heated sample and the equilibrium temperature as the change in temperature in the sample. Given the known mass, the beginning temperature of the water, and the equilibrium temperature I can determine how much energy was transferred from the heated sample to the water.
Now the mass of the sample, a change in temperature in the solid substance, and the amount of energy transferred to create the temperature is known. This is sufficient to determine the specific heat of the solid substance</span>
When the element in group 1 are considered in order from top to bottom, each successive Elmer at standard pressure has a lower melting point and a lower boiling point.
Answer:
2.83 g
Explanation:
At constant temperature and pressure, Using Avogadro's law
Given ,
V₁ = 2.12 L
V₂ = 3.12 L
n₁ = 0.120 moles
n₂ = ?
Using above equation as:
n₂ = 0.17660 moles
Molar mass of methane gas = 16.05 g/mol
So, Mass = Moles*Molar mass = 0.17660 * 16.05 g = 2.83 g
<u>2.83 g are in the piston.</u>
Answer:
Explanation:
Glucose + ATP → glucose 6-phosphate + ADP The equilibrium constant, Keq, is 7.8 x 102.
In the living E. coli cells,
[ATP] = 7.9 mM;
[ADP] = 1.04 mM,
[glucose] = 2 mM,
[glucose 6-phosphate] = 1 mM.
Determine if the reaction is at equilibrium. If the reaction is not at equilibrium, determine which side the reaction favors in living E. coli cells.
The reaction is given as
Glucose + ATP → glucose 6-phosphate + ADP
Now reaction quotient for given equation above is
![q=\frac{[\text {glucose 6-phosphate}][ADP]}{[Glucose][ATP]}](https://tex.z-dn.net/?f=q%3D%5Cfrac%7B%5B%5Ctext%20%7Bglucose%206-phosphate%7D%5D%5BADP%5D%7D%7B%5BGlucose%5D%5BATP%5D%7D)
so,
⇒ following this criteria the reaction will go towards the right direction ( that is forward reaction is favorable until q = Keq
