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2 years ago

A plasma membrane and a cell wall _____.

Chemistry

2 answers:

klemol [59]2 years ago

5 0

<h3>Answer;</h3>

D. Have different structures and different functions

A plasma membrane and a cell wall have different structures and different functions.

<h3>Explanation;</h3>

Plasma membrane is a structure that is found in both animal cell and plants cells. It is made up of a bi-layer consisting of lipid and proteins. Plasma membrane are semi-permeable which means the allow selective movement of materials in and out of the cell.

Cell wall, on the other hand is a structure that is found on plant cells and lacks in animal cell. It contains cellulose in its structure which enables it to be rigid and enhances it protect the cell from mechanical damage from harsh conditions such as pressure in the outside environment.

murzikaleks [220]2 years ago

5 0

A plasma membrane and a cell wall have different structures and different functions.

Further Explanation:

Plasma membrane present in all the animals and plants. A cell wall covers the plasma membrane in plants. The plasma membrane is mainly made up of lipid bilayer which is semi-permeable to some molecule, ions and gases. Through this, the plasma membrane regulates the efflux and influx of a molecule.

Major functions of a plasma membrane are:

Maintain the structure of a cell.
Help in interaction with other cells.
Protect outside.
Help in the transport of toxic and nutrient substances or chemicals out of the cell.

The cell wall is the outermost covering of the cell. They are made up of hemicelluloses and cellulose, which provide the plant cell with extra support and protection. The cell wall is not present in an animal cell. The prokaryotic cell wall provides more protection than the eukaryotic cell wall. They help to maintain the shape of a cell and provide defense against dehydration.

Learn more:

Learn more about cell organelle brainly.com/question/5923583
Learn more about the diffusion brainly.com/question/1386629
Learn more about the plant brainly.com/question/862697

Answer Details:

Grade: High School

Subject: Biology

Chapter: Plant Cell

Keywords:

Plant cell, animal cell, cell wall, plasma membrane, dehydration, covering, shape, chemical, protection, defense, efflux, influx, lipid bilayer, semi-permeable.

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2 years ago

A mysterious white powder could be powdered sugar (C12H22O11), cocaine (C17H21NO4), codeine (C18H21NO3), norfenefrine (C8H11NO2)

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Norfenefrine (C₈H₁₁NO₂).

<h3>Further explanation</h3>

We will solve a case related to one of the colligative properties, namely freezing point depression.

The freezing point of the solution is the temperature at which the solution begins to freeze. The difference between the freezing point of the solvent and the freezing point of the solution is called freezing point depression.

$\boxed{ \ \Delta T_f = T_f(solvent) - T_f(solution) \ } \rightarrow \boxed{ \ \Delta T_f = K_f \times molality \ }$

Given:

A mysterious white powder could be,

powdered sugar (C₁₂H₂₂O₁₁) with a molar mass of 342.30 g/moles,
cocaine (C₁₇H₂₁NO₄) with a molar mass of 303.35 g/moles,
codeine (C₁₈H₂₁NO₃) with a molar mass of 299.36 g/moles,
norfenefrine (C₈H₁₁NO₂) with a molar mass of 153.18 g/moles, or
fructose (C₆H₁₂O₆) with a molar mass of 180.16 g/moles.

When 82 mg of the powder is dissolved in 1.50 mL of ethanol (density = 0.789 g/cm³, normal freezing point −114.6°C, Kf = 1.99°C/m), the freezing point is lowered to −115.5°C.

Question: What is the identity of the white powder?

The Process:

Let us identify the solute, the solvent, initial, and final temperatures.

The solute = the powder
The solvent = ethanol
The freezing point of the solvent = −114.6°C
The freezing point of the solution = −115.5°C

Prepare masses of solutes and solvents.

Mass of solute = 82 mg = 0.082 g
Mass of solvent = density x volume, i.e., $\boxed{ \ 0.789 \ \frac{g}{cm^3} \times 1.50 \ cm^3 = 1.1835 \ g = 0.00118 \ kg \ }$

We must prepare the solvent mass unit in kg because the unit of molality is the mole of the solute divided by the mass of the solvent in kg.

The molality formula is as follows:

$\boxed{ \ m = \frac{moles \ of \ solute}{kg \ of \ solvent} \ } \rightarrow \boxed{ \ m = \frac{mass \ of \ solute \ (g)}{molar \ mass \ of \ solute \times kg \ of \ solvent} \ }$

Now we combine it with the formula of freezing point depression.

$\boxed{ \ \Delta T_f = K_f \times \frac{mass \ of \ solute \ (g)}{molar \ mass \ of \ solute \times kg \ of \ solvent} \ }$

It is clear that we will determine the molar mass of the solute (denoted by Mr).

We enter all data into the formula.

$\boxed{ \ -114.6^0C - (-115.5^0C) = 1.99 \frac{^0C}{m} \times \frac{0.082 \ g}{Mr \times 0.00118 \ kg} \ }$

$\boxed{ \ 0.9 = \frac{1.99 \times 0.082}{Mr \times 0.00118} \ }$

$\boxed{ \ Mr = \frac{0.16318}{0.9 \times 0.00118} \ }$

We get $\boxed{ \ Mr = 153.65 \ }$

These results are very close to the molar mass of norfenefrine which is 153.18 g/mol. Thus the white powder is norfenefrine.

<h3>Learn more</h3>

The molality and mole fraction of water brainly.com/question/10861444
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Keywords: a mysterious white powder, sugar, cocaine, codeine, norfenefrine, fructose, the solute, the solvent, dissolved, ethanol, normal freezing point, the freezing point depression, the identity

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2 years ago

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Akimi4 [234]

Answer:

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Explanation:

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It is possible to sum ΔH of different reactions to obtain ΔH of a global reaction (Hess's law).

For the reactions:

(2) N₂(g) + 4H₂(g) + Cl₂(g) → 2NH₄Cl(s) ΔH°rxn = −630.78 kJ/mol

(3) N₂(g) + 3H₂(g) → 2NH₃(g) ΔH°rxn = −296.4 kJ/mol

The sum of -(2) + (3) gives:

-(2) 2NH₄Cl(s) → N₂(g) + 4H₂(g) + Cl₂(g) ΔH°rxn = +630.78 kJ/mol

(3) N₂(g) + 3H₂(g) → 2NH₃(g) ΔH°rxn = −296.4 kJ/mol

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NH₄Cl(s) → NH₃(g) + HCl(g)

Has ΔH°rxn = 149,78kJ/mol / 2 = 74,89 kJ/mol

I hope it helps!

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2 years ago

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beks73 [17]

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Brut [27]

Answer:

Check the image in the file attached below.

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