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2 years ago

One molecule of a compound weighs 2.03x10-22 g. what is the molar mass of that compound?

Chemistry

2 answers:

Sloan [31]2 years ago

7 0

The molar mass of the given compound is $\boxed{122.2{\text{ g/mol}}}$ .

Further Explanation:

Molar mass:

The molar mass is the summation of masses of all atoms or molecule present in the 1 mole of compound. In other words, molar mass of a compound is the ratio of mass of compound in grams to the number of moles present of that compound. The S.I unit of molar mass is gram per mol or g/mol.

Mass of one molecule of a given compound is $2.03\times{10^{-22}}{\text{g}}$ .

According to Avogadro's number, the number of atoms or molecules present in the 1 mole of a substance is ${\mathbf{6}}{\mathbf{.022\times1}}{{\mathbf{0}}^{{\mathbf{23}}}}$ .

Therefore, to calculate the mass of 1 mole of atoms, we have to multiply the mass of one molecule with the number of molecules present in 1 mole of given compound that is $6.022\times{10^{23}}$ .

The calculation for molar mass gives as follows:

$\begin{gathered} {\text{Molar mass}} = \left( {{\text{mass of 1 molecule}}\left( {\text{g}} \right)} \right)\left({{\text{number of molecules in 1 mole substance}}}\right)\\=\left({2.03\times{{10}^{-22}}{\text{g}}}\right)\left({6.022\times{{10}^{23}}{\text{ mo}}{{\text{l}}^{-1}}}\right)\\=\left({2.03\times 6.022}\right)\times{\text{1}}{{\text{0}}^{-22+23}}{\text{ g/mol}}\\=122.2{\text{ g/mol}}\\\end{gathered}$

The value mass of 1 mole of given molecule is 122.2 g/mol.

Learn more:

1. Determined the mass of ammonia product formed in the reaction: brainly.com/question/6078553

2. Determine how many moles of water produce: brainly.com/question/1405182

Answer details:

Grade: Senior school

Subject: Chemistry

Chapter: Mole concept

Keywords: Potassium, molar mass, moles, atomic mass, number of moles, number of atoms, given mass, ratio, substance, g/mol grams, 78.20 grams, 2 moles, 39.098 g/mol, number of moles of potassium.

stealth61 [152]2 years ago

6 0

<span>The molar mass of the compound is 122 g. </span>

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How many grams of calcium cyanide (Ca(CN)2) are contained in 0.79 mol of calcium cyanide?

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2 years ago

If this decay has a half life of 2.60 years, what mass of 72.5 g of sodium 22 will remain after 15.6 years

Vlad1618 [11]

Sodium-22 remain : 1.13 g

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.

Usually, radioactive elements have an unstable atomic nucleus.

General formulas used in decay:

$\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{T/t\frac{1}{2} }}}$

T = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

half-life = t 1/2=2.6 years

T=15.6 years

No=72.5 g

$\tt Nt=72.5.\dfrac{1}{2}^{15.6/2.6}\\\\Nt=72.5.\dfrac{1}{2}^6\\\\Nt=1.13~g$

8 0

2 years ago

Groups of atoms that are added to carbon backbones and give them unique properties are known as

Irina-Kira [14]

Answer:

Groups of atoms that are added to carbon backbones and give them unique properties are known as <u>Functional Groups</u>.

Explanation:

In organic chemistry they are called as Functional Group because they are the active part of a molecule. These groups give a unique characteristic to molecule both chemically and physically. Also, each functional group represent a different class of compounds.

Examples:

S No. Functional Group Name

1 R--X Alkyl Halides

2 R--OH Alcohols

3 R--NH₂ Amines

4 R--O--R Ethers

5 R--CO--R Ketones

6 R--CO--H Aldehydes

7 R--CO--OH Carboxylic acids

8 R--CO--X Acid Halides

10 R--CO--NR₂ Acid Amides

11 R--CO-OR' Esters

3 0

2 years ago

In addition to the separation techniques used in this lab (magnetism, evaporation, and filtering), there are other commonly used

DENIUS [597]

Answer:

A. Water and Sugar can be separated by evaporation and then crystallization

B. Mixture of Hexane and Octane can be separated by distillation

C. Solid Iodine, I₂ and NaCl can be separated by filtration and then evaporation

D. "Sharpie" permanent marking pen can be separated by chromatography

E. Nickel shavings and copper pellets can be separated by magnetic separation

Explanation:

A. A mixture of water and sugar can be separated by employing two separation techniques, evaporation and crystallization. First the sugar solution is heated to evaporate most of the water. When the solution becomes very saturated, it is allowed to cool and then the sugar molecules are obtained through crystallization induced by seeding or scratching the walls of the container.

B. A mixture of hexane (boiling point = 68 °C) and Octane (boiling point = 125 °C) can be separated by distillation due to their significant difference in boiling points.

The mixture is heated in a flask connected to a Liebig condenser. Hexane with the lower boiling point will distill over first and is collected. Afterwards, octane next distills over and is collected as well.

C. A mixture of solid iodine and NaCl can be seperated by first dissolving in water. Iodine being non- polar does not dissolve and is collected as a residue from filtration using a filter paper, while the NaCl solution is collected as the filtrate. The NaCl is recovered from solution by evaporating to dryness in an evaporating dish.

D. "Sharpie" permanent marking pen contains a mixture of dyes which can be separated by paper chromatography.

A drop of the marker ink is placed on a spot above the solvent level on the paper strip used for the separation. The paper strip is held vertically inside a jar containing a solvent which serves as the mobile phase. The jar is covered and the different dyes move along the paper which serves as the stationary phase, and is thus separated. The paper strip is removed from the jar when the ascending front of the solvent is approaching the top of the paper. The paper is dried and the various dyes can be identified by comparing the distance each has traveled with those of standards.

E. A mixture of nickel shavings and copper pellets can be separated by magnetic separation.

A magnet is brought near the mixture and the nickel shavings being magnetic is attracted to the magnet leaving copper pellets behind since copper is not magnetic.

4 0

2 years ago

Each day, the stomach produces 2.0 L of gastric juice that contains 0.10 M HCl. Phillips Milk of Magnesia is a white-colored, aq

trasher [3.6K]

Answer:

It would take 72.9 mL of milk of magnesia.

Explanation:

First of all we have to think how the compounds react with each other and what are the products formed. In this case, the hydrochloric acid reacts with magnesium hydroxide to generate magnesium chloride and water as a subproduct. Having said that, we have to state the balanced chemical reaction to know the associated stoichiometry:

2 HCl + Mg(OH)2 → MgCl2 + 2 H2O

According to the balanced equation we know that 2 mol of HCl reacts with 1 mol of Mg(OH)2.

Now we calculate the quantity of moles of HCl that we have present in 2.0 lts of 0.10 M solution:

0.1 M HCl = 0.1 moles HCl / 1000 ml Solution

So, in 2 liters of solution we will have 0.2 moles of HCl

This 0.2 moles of acid, as we stated before, will react with 0.1 moles of Mg(OH)2, so we need to calculate the amount of milk of magnesia that has this required quantity of moles.

With the molar mass of Mg(OH)2 we calculate the weight of the compound that represents the 0.1 moles needed to react with all the HCl present in solution:

1 mol Mg(OH)2 = 58.32 g

0.1 mol = 5.832 g

Now we need to determine what volume of the milk of magnesia solution has 5.832 g of Mg(OH)2 to react with the acid:

The concentration of milk of magnesia is 8 % (w/v). This means that we have 8 gr of Mg(OH)2 per 100 ml of solution.

8 gr Mg(OH)2 per 100 mL Solution

5.832 gr Mg(OH)2 = 72.9 mL of Milk of Magnesia

6 0

2 years ago