Answer:
The atomic mass of the given metal M is 24.3 g/mol.
Therefore, the given metal M is magnesium (Mg)
Explanation:
Reaction involved: MSO₄ + BaCl₂ → BaSO₄ + MCl₂
Atomic mass (g/mol): oxygen (O)=16, sulphur (S)=32,
Molar mass of SO₄²⁻ = 96 g/mol and molar mass of BaSO₄ = 233.38 g/mol
Let the atomic mass of M be m g/mol.
Therefore, molar mass of MSO₄= (m + 96) g/mol
If 0.1131 g of MSO₄ gives 0.2193 g of BaSO₄ on reaction
Then, (m + 96) g/mol of MSO₄ gives 233.38 g/mol of BaSO₄
Therefore, (m + 96) g/mol of MSO₄ = [(233.38 g/mol) × (0.1131 g)] ÷ (0.2193 g)
⇒(m + 96) g/mol = [26.395] ÷ (0.2193)
⇒(m + 96) g/mol = 120.36 g/mol
⇒m = 120.36 g/mol - 96 g/mol = 24.36 g/mol ≈ 24.3 g/mol
<u>Since, the atomic mass of the given metal M is 24.3 g/mol</u>.
<u>Therefore, the given metal M is magnesium (Mg)</u>
