Question

Sugar is easily soluble in water and has a molar mass of 342.30 g/mol. What is the molar concentration of a 259.8 mL aqueous solution prepared with 73.1 g of sugar?

Answer 1

Answer:

$M=0.822M$

Explanation:

Hello,

In this case, given the mathematical definition of molar concentration as the moles of solute divided by the liters of solution:

$M=\frac{n}{V}$

We can easily compute it by firstly computing the moles of sugar by using its molar mass:

$n=73.1g*\frac{1mol}{342.30g} =0.214mol$

After that, we compute the concentration by realizing 259.8 mL equals 0.2598 L:

$M=\frac{0.214mol}{0.2598L}\\ \\M=0.822mol/L$

Or just:

$M=0.822M$

Considering molar units as mol/L

Best regards.