Question

Calculate the mass of hydrazine (N2H4) that contains a billion (1.000 x 10^9) hydrogen atoms.

Answer 1

Answer: The mass of hydrazine having 1 billion hydrogen atoms is $1.328\times 10^{-14}g$

Explanation:

Molar mass of hydrazine = 32 g/mol

We are given:

A chemical compound having formula $N_2H_4$

1 mole of hydrazine contains 2 moles of nitrogen atoms and 4 moles of hydrogen atoms

Number of hydrogen atoms = $1.000\times 10^9$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules.

So, 1 mole of hydrazine will contain = $4\times 1\times 6.022\times 10^{23}=2.4088\times 10^{24}$ number of hydrogen atoms.

Thus, mass of $2.4088\times 10^{24}$ number of hydrogen atoms present in hydrazine is 32 grams

So, mass of $1.000\times 10^9$ number of hydrogen atoms present in hydrazine will be = $\frac{32g}{2.4088\times 10^{24}}\times 1.000\times 10^9=1.328\times 10^{-14}g$

Hence, the mass of hydrazine having 1 billion hydrogen atoms is $1.328\times 10^{-14}g$

Answer 2

Answer:

1.3285 × 10⁻¹⁴ g of hydrazine

Explanation:

if         32 g of hydrizine (1 mole) contains 4 × 6.022  × 10²³ hydrogen atoms

then     X g of hydrizine contains 1 × 10⁹ hydrogen atoms

X = (32 × 1 × 10⁹) / (4 × 6.022  × 10²³)

X = 1.3285 × 10⁻¹⁴ g of hydrazine