Answer:
a

b

Explanation:
From the question we are told that
The pressure of compressed gas is 
The temperature is 
Generally the perfect gas equation is mathematically represented as

substituting 0.08206 L-atm/mol-K for R and 1 mole for n
We have that


Generally the van der Waals equation is mathematically represented as
![nRT = [P + \frac{n^2 * a }{V^2 } ][V - nb]](https://tex.z-dn.net/?f=nRT%20%20%3D%20%20%5BP%20%2B%20%5Cfrac%7Bn%5E2%20%2A%20a%20%7D%7BV%5E2%20%7D%20%5D%5BV%20-%20nb%5D)
=>![1 * 0.08206 *298 = [197.4 + \frac{1^2 * 1.364}{V^2 } ][V - 1 * 3.19 * 10^{-2}]](https://tex.z-dn.net/?f=1%20%2A%20%200.08206%20%2A298%20%20%3D%20%20%5B197.4%20%2B%20%5Cfrac%7B1%5E2%20%2A%20%201.364%7D%7BV%5E2%20%7D%20%5D%5BV%20-%201%20%2A%203.19%20%2A%2010%5E%7B-2%7D%5D)
=> 
Answer: 0.70g
The half-life of iron-53 would be 8.51 minutes. So, in 25.53 minutes would be equal to: 25.53 min/ (8.51 minutes/ half-life)= 3 half-life.
Every half-life will reduce the original weight into half. So, the final weight would be:
final weight = original weight * 1/2 ^(time)
final weight = 5.6g * (1/2)^(3 half-life)
final weight = 5.6g * 1/8= 0.7g
The volume of the brick in cubic meters is 0.00108 m³
<u><em>calculation</em></u>
<u><em> </em></u> volume of a brick =length x width x height
-length = 15 cm
width = 6.0 cm
height = 12 cm
volume is therefore= 15 cm x 6.0 cm x 12 cm =1080 cm³
convert 1080 cm³ into m³
that is 1 cm³ = 1 x 10^-6m³
1080 cm³ = ? m³
by cross multiplication
=[ (1080 cm³ x 1 x10^-6 m³) / 1 cm³] = 0.00108 m³
If a runner completes a 10 km race in 32.5 minutes, his pace or speed can be calculated by the equation:
velocity = distance/time = 10km/32.5 mins = 0.3125 km/min
Convert this value to miles per hour using the conversion factors for minutes to hours and kilometers to miles as requested by the problem. This gives an answer of 11.47 miles per hour.
0.3125 km/min x 60 mins./ 1 hour x 1 mile / 1.609 km = 11.47 miles/hour
Answer:
1. Molecular equation
BaCl2(aq) + 2AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)
2. Complete Ionic equation
Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯(aq)
3. Net ionic equation
Cl¯(aq) + Ag⁺(aq) —> AgCl(s)
Explanation: