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Tpy6a [65]
2 years ago
14

Determine the number of bonding electrons and the number of nonbonding electrons in the structure of cs2.

Chemistry
2 answers:
Rus_ich [418]2 years ago
5 0

The number of bonding and non-bonding electrons in {\text{C}}{{\text{S}}_2} are \boxed8 and \boxed8 respectively.

Further explanation:

In order to determine the number of bonding and non-bonding electrons first, we need to draw the correct Lewis structure of {\text{C}}{{\text{S}}_2} the molecule.

The Lewis structure is the chemical representation of an element along with the nonbonding pairs. For covalent molecules, the number of electrons involved in bonding and the remaining nonbonding pairs can be represented while writing the Lewis structures. Lewis structures help predict the geometry, polarity, and reactivity of the molecules.

The central atom is usually the least electronegative atom other than hydrogen. Hence out of carbon and sulphur, the former will act as the central metal atom. So arrange the two sulphur atoms around the carbon. Next, determine the number of valence electrons.

The total number of valence electrons of {\text{C}}{{\text{S}}_2} is calculated as,

{\text{Total valence electrons}} = \left[ {\left( {\text{1}} \right)\left( {{\text{Valence electrons of Carbon}}} \right){t{ + }}\left( 2 \right)\left( {{\text{Valence electrons of sulphur}}} \right)} \right]  

Since carbon carries 4 valence electron and sulphur carries 6 valence electrons. So,

\begin{aligned}{\text{Total valence electrons}}\left( {{\text{TVE}}} \right) &= \left[ {\left( 1 \right)\left( 4 \right)+\left( 2\right)\left( 6 \right)}\right]\\&= 16\\\end{aligned}  

Lewis structure of {\mathbf{C}}{{\mathbf{S}}_{\mathbf{2}}} and its linear shape along with the bonding and non-bonding electron pairs is apparent in the attached image.

Out of 16 electrons, eight electrons are involved in the formation of four bonds between the carbon and two sulfur atom. Carbon forms one sigma and one pi bond with each sulfur atom respectively. So now we are left with 8 electrons. These will constitute the non-bonding (lone pairs). 2 lone are present on each sulfur atom.

Learn more:

1. Coordination number for lithium sulfide crystals: brainly.com/question/75586212

2. Scientific notation: brainly.com/question/4935921

Answer details:  

Grade: High School

Subject: Chemistry

Chapter: Molecular structure and chemical bonding.

Keywords: Lewis structure, valence electrons, CS2, a single bond, bonding electrons, non-bonding electrons, and total valence electrons.

trapecia [35]2 years ago
3 0
Carbon disulfide ( S=C=S)  is made up of one carbon atom and two sulfur atom. 
Carbon has 4 valence electrons while sulfur has 6 electrons. 
During bonding all the four carbon valence electrons are used in bonding while each sulfur atom contributes two electrons two the bond formation.
Therefore; 4 + 2(2) = 8 electrons are used for bonding, while 8 electrons ( four from each sulfur atom) are not used for bond formation. 
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Carbon monoxide and molecular oxygen react to form carbon dioxide. A 50.0 L reactor at 25.0 oC is charged with 1.00 bar of CO. T
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Answer:

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CO2 =1 bar

O2  = 2.02 bar

Explanation:

We are given

initial pressure of CO = 1bar

total pressure = 3.52 bar

so initial pressure of O2 = 3.52 - 1 = 2.52 bar

the reaction is

2CO + O2 →  2CO2

using the unitary method

2 moles of CO2 → 1 mole of O2

1  bar of CO → \frac{1}{2} * 1= 0.5 bar (required)

but we have more oxygen present , that means CO is the limiting reagent

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Which of the compounds above are strong enough acids to react almost completely with a hydroxide ion (pka of h2o = 15.74) or wit
luda_lava [24]

The compounds can react with OH⁻ and HCO₃⁻ only C₅H₆N pyridinium

<h3><em>Further explanation </em></h3>

In an acid-base reaction, it can be determined whether or not a reaction occurs by knowing the value of pKa or Ka from acid and conjugate acid (acid from the reaction)

Acids and bases according to Bronsted-Lowry

Acid = donor (donor) proton (H + ion)

Base = proton (receiver) acceptor (H + ion)

If the acid gives (H +), then the remaining acid is a conjugate base because it accepts protons. Conversely, if a base receives (H +), then the base formed can release protons and is called the conjugate acid from the original base.

From this, it can be seen whether the acid in the product can give its proton to a base (or acid which has a lower Ka value) so that the reaction can go to the right to produce the product.

The step that needs to be done is to know the pKa value of the two acids (one on the left side and one on the right side of the arrow), then just determine the value of the equilibrium constant

Can be formulated:

K acid-base reaction = Ka acid on the left : K acid on the right.

or:

pK = acid pKa on the left - pKa acid on the right

K = equilibrium constant for acid-base reactions

pK = -log K;

K~=~10^{-pK}

K value> 1 indicates the reaction can take place, or the position of equilibrium to the right.

There is some data that we need to complete from the problem above, which is the pKa value of some compounds that will react, namely:

pyridinium pKa = 5.25

acetone pKa = 19.3

butan-2-one pKa = 19

Let's look at the K value of each possible reaction:

pka H₂O = 15.74, pka of H₂CO₃ = 6.37)

  • 1. C₅H₆N pyridinium

* with OH⁻

C₅H₆N + OH- ---> C₅H₅N- + H₂O

pK = pKa pyridinium - pKa H₂O

pK = 5.25 - 15.74

pK = -10.49

K~=~10^{4.9}

K values> 1 indicate the reaction can take place

* with HCO3⁻

C₅H₆N + HCO₃⁻-- ---> C₅H₅N⁻ + H₂CO₃

pK = 5.25 - 6.37

pK = -1.12

K`=~10^{1.12]

Reaction can take place

  • 2. Acetone C₃H₆O

* with OH-

C₃H₆O + OH⁻ ---> C₃H₅O- + H₂O

pK = 19.3 - 15.74

pK = 3.56

K~=~10^{ -3.56}

Reaction does not happen

* with HCO₃-

C₃H₆O + HCO₃⁻ ----> C₃H₅O⁻ + H₂CO₃

pK = 19.3 - 6.37

pK = 12.93

K`=~10 ^{-12.93}

Reaction does not happen

  • 3. butan-2-one C₄H₇O

* with OH-

C₄H₇O + OH- ---> C₄H₆O- + H₂O

pK = 19 - 15.74

pK = 3.26

K~=~10^{-3.26}

Reaction does not happen

* with HCO₃⁻

C₄H₇O + HCO₃⁻ ---> C₄H₆O⁻ + H₂CO₃

pK = 19 - 6.37

pK = 12.63

K~=~ 10^{-12.63}

Reaction does not happen

So that can react with OH⁻ and HCO₃⁻ only C₅H₆N pyridinium

<h3><em>Learn more </em></h3>

the lowest ph

brainly.com/question/9875355

the concentrations at equilibrium.

brainly.com/question/8918040

the ph of a solution

brainly.com/question/9560687

Keywords : acid base reaction, the equilibrium constant

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