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gizmo_the_mogwai [7]
2 years ago
7

The ground tends to be warmer on a sunny day than on cloudy one . What is the primary type of thermal energy transfer that cause

s this?
A. Insulation
B. Radiation
C. Conduction
D. Convection
Biology
2 answers:
Triss [41]2 years ago
6 0
b. Radiation is the answer
ipn [44]2 years ago
4 0

Answer:

The answer is Radiation.

Explanation:

The answer would be radiation. Radiation is an emission or transmission of energy in the form of particles that move very quickly. These can cross space or matter. The heat of the sun can be translated into these energy particles that move very quickly. Eventually, this energy manages to make contact with the earth's atmosphere, and is transferred, through radiation, to the ground. That is why on sunny days, the earth pulsed to be warmer than on cloudy days, since the emission of solar radiation is blocked by clouds in the sky.

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The expansion of grasses during the Oligocene and Miocene Epochs led to
tresset_1 [31]

Answer:

The answer is:

D. the radiation of herbivores such as grazing animals

Explanation:

Oligocene and Miocene Epochs:

  • The Oligocene epoch is characterized by temperate and subtropical climatic conditions which favored the expansion of grasses and reduced forest cover.
  • The Miocene epoch, which succeeded the Oligocene era, is attributed to changes in global circulation due to global warming of the climate followed by global cooling towards the end.

The Oligocence and Miocene epoch are both attributed to the expansion of grasslands and savannah. Both eras marked rapid and drastic evolutionary changes in grazing mammals and herbivores. Diverse groups of grazing mammals lived throughout these eras. For example, the largest herbivore and land mammal of all time, <em>Indricotherium</em> (a sort of giant hornless rhinoceros), was present in the Oligocene era.

Similarly, the Oligocene era in North America favored the rapid radiation of primitive horses.

8 0
2 years ago
Plants that evolved vascular tissue are more advanced than plants without vascular tissue. Most importantly, possession of vascu
aliya0001 [1]

Answer:

The correct answer will be option-D

Explanation:

The evolution of vascular tissues in plants from non-vascular plants was an adaptive feature to survive in the terrestrial environment.  The group of plants in which vascular tissues evolved and developed is the Pteridophytes which contained stellar organization of the vascular bundles.

The pteridophytes exhibited xylem and phloem which allows the rapid uptake of the water and nutrients from the soil which allowed the growth of the plant and since plants got enough water and nutrients from the soil, they adapted to grow tall so that they can maximize the output of photosynthesis in bright sunshine.

Thus, option-D is the correct answer.

6 0
2 years ago
Black mice and tan mice are native species that are observed in a particular region. Human habitation in the region caused an in
4vir4ik [10]

Answer:

A

Explanation:

The correct answer would be that <u>the availability of food resources for black mice and brown mice will decrease.</u>

<em>Since the food requirements of the black mice are the same as that of the invasive brown mice, the available food supply that used to be only for the black mice would now be shared by the two strains of mice. Hence, the available food for the two groups of mice will naturally decrease.</em>

There is no sufficient information to conclude that the population of tan mice will decrease, hence, option B is incorrect.

The black mice and tan mice have different food requirements going by the information available in the illustration, hence, both cannot compete for food resources. Option C is, therefore, incorrect. In the same vein, option D is incorrect because the tan mice have different food requirements from the brown mice.

<u>The only correct option is A.</u>

3 0
2 years ago
Which procedures were followed in this lab to decrease experimental error? Check all that apply. repeating the experiment three
Musya8 [376]
<span>repeating the experiment three times for each temperature

</span><span>using three different temperatures instead of only two

</span><span>using three different surface areas instead of only two

hope this helps</span>
3 0
2 years ago
Read 2 more answers
Enolase is an enzyme that catalyzes one reaction in glycolysis in all organisms that carry out this process. The amino acid sequ
lorasvet [3.4K]

Answer:

a) The response indicates that a pH below or above this range will most likely cause enolase to denature/change its shape and be less efficient or unable to catalyze the reaction.

b)The response indicates that the appropriate negative control is to measure the reaction rate (at the varying substrate concentrations) without any enzyme present.

c)The response indicated that the enolase has a more stable/functional/correct/normal protein structure at the higher temperature of 55°C than at 37°C because the enzyme is from an organism that is adapted to growth at 55°C.

Explanation:

Enolase catalyzes the conversion of 2-phosphoglycerate to phosphoenolpyruvate during both glycolysis and gluconeogenesis.In bacteria, enolases are highly conserved enzymes and commonly exist as homodimers.

The temperature optimum for enolase catalysis was 80°C, close to the measured thermal stability of the protein which was determined to be 75°C, while the pH optimum for enzyme activity was 6.5. The specific activities of purified enolase determined at 25 and 80°C were 147 and 300 U mg−1 of protein, respectively. Km values for the 2-phosphoglycerate/phosphoenolpyruvate reaction determined at 25 and 80°C were 0.16 and 0.03 mM, respectively. The Km values for Mg2+ binding at these temperatures were 2.5 and 1.9 mM, respectively.

Enolase-1 from Chloroflexus aurantiacus (EnoCa), a thermophilic green non-sulfur bacterium that grows photosynthetically under anaerobic conditions. The biochemical and structural properties of enolase from C. aurantiacus are consistent with this being thermally adapted.

8 0
2 years ago
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