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stellarik [79]
2 years ago
12

For no2−, write an equation that shows how the anion acts as a base. express your answer as a chemical equation. identify all of

the phases i
Chemistry
2 answers:
Diano4ka-milaya [45]2 years ago
6 0

Explanation:

According to Arrhenius, bases are the species which when dissolved in water will give hydroxide ions, that is, OH^{-}.

On the other hand, species which tend to dissociate in water to given hydrogen ions, that is, H^{+} ions are known as acids.

So, in the given situation NO^{-}_{2} is the anion. And, when when it is added to water the it will combine with a hydrogen atom and results in the formation of HNO_{2}.

The reaction equation will be as follows.

   NO^{-}_{2}(aq) + H_{2}O(l) \rightarrow HNO_{2}(aq) + OH^{-}(aq)

katrin [286]2 years ago
5 0
Hello!

Bases are defined by Arrhenius as substances which release OH⁻ ions when dissolved in water. NO₂⁻ complies with this definition by the chemical reaction that is shown below:

 NO₂⁻(aq) + H₂O (l) HNO₂ (aq) + OH⁻(aq)

Have a nice day!
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0.9775 grams of an unknown compound is dissolved in 50.0 ml of water. Initially the water temperature is 22.3 degrees Celsius. A
elena-14-01-66 [18.8K]

Answer:

The enthlapy of solution is -55.23 kJ/mol.

Explanation:

Mass of water = m

Density of water = 1 g/mL

Volume of water = 50.0 mL

m = Density of water × Volume of water = 1 g/mL × 50.0 mL=50.0 g

Change in temperature of the water ,ΔT= 27.0°C - 22.3°C = 4.7°C

Heat capacity of water,c =4.186 J/g°C

Heat gained by the water when an unknown compound is dissolved be Q

Q= mcΔT

Q=50.0 g\times 4.186 J/g^oC\times 4.7^oC=983.71 J

heat released when 0.9775 grams of an unknown compound is dissolved in water will be same as that heat gained by water.

Q'=-Q

Q'= -983.71 J =-0.98371 kJ

Moles of unknown compound = \frac{0.9975 g}{56 g/mol}=0.01781 mol

The enthlapy of solution :

\frac{Q'}{moles}

=\frac{-0.98371 kJ}{0.01781 mol}=-55.23 kJ/mol

The enthlapy of solution is -55.23 kJ/mol.

8 0
2 years ago
A particular first-order reaction has a rate constant of 1.35 × 102 s-1 at 25.0°c. what is the magnitude of k at 75.0°c if ea =
IgorC [24]
According to this formula:
K= A*(e^(-Ea/RT) when we have K =1.35X10^2 & T= 25+273= 298K &R=0.0821
Ea= 85.6 KJ/mol So by subsitution we can get A:
1.35x10^2 = A*(e^(-85.6/0.0821*298))
1.35x10^2 = A * 0.03
A= 4333
by substitution with the new value of T(75+273) = 348K & A to get the new K
∴K= 4333*(e^(-85.6/0.0821*348)
  = 2.16 x10^2
8 0
2 years ago
Why couldn't you substitute 3m H2SO4 for concentrated HNO3 when oxidizing copper?
schepotkina [342]

This question seems to be an essay question from experiment. Different solution of oxidizing agent will have different strength.  Sulfuric acid or H2SO4 is weaker oxidizing agent when compared to nitric acid (HNO3). In this case, if you subtitute the H2SO4 you wouldn't be able to get the same result for the experiment.



5 0
2 years ago
Read 2 more answers
PLEAS HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! DUE TONIGHT
Jobisdone [24]

Answer:

It is required answer.

Explanation:

Given that :

1. using balanced chemical equation:

ammonium acetate:

The balanced equation is:

NH₃ + H₂O ===> NH₄OH

when ammonia gas dissolves in water then we get the base in form of ammonium hydroxide.

When  NH₄OH reacts with CH₃COOH then we get ammonium acetate and water

NH₄OH + CH₃COOH ===> [CH₃COO]- & NH₄+ & H₂O

So, we can say that,

when we are adding an acid and a base together then we get the product of H₂O and given elements.

2. addition of barium hydroxide to sulfuric acid:

the balanced equation is

H₂SO4+ Ba(OH)₂--> BaSO₄+ 2H₂O

when acid and base reacts together than we get barium sulphate and water

when sulfuric acid and barium hydroxide.

Hence, it is required answer.

8 0
2 years ago
Which is stronger, the strong force (SF) or the electromagnetic force (EMF)? Describe how they battle each other in the nucleus.
Roman55 [17]

Answer:uclear Force that holds together the nucleus of an atom. electromagnetic force. ... They are unstable because the Strong Force that would hold them together if the protons and neutrons were closer is weakened because the protons and neutrons get too far apart.

Explanation:

6 0
2 years ago
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