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katovenus [111]

2 years ago

15

The smiths spent $2,000 on clothes in a particular year. if they increase the amount they spend on clothes by 10% each year, the

smiths will spend a total of $ on clothing in 4 years. nextreset

1 answer:

dsp732 years ago

8 0

First year $2000

1- $2200

2- $ 2420

3- $2662

4- $2,928.2

good luck

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If Line segment C B. bisects ∠ACD, what additional information could be used to prove ΔABC ≅ ΔDBC using SAS? Select three option

meriva

Answer:

Option (1)

Step-by-step explanation:

In the figure attached,

BC is the angle bisector of angle ACD.

To prove ΔABC and ΔDBC congruent by SAS property we require two sides and the angle between these sides to be congruent.

Since BC ≅ BC [Reflexive property]

∠ABC ≅ ∠CBD ≅ 125°

And sides AB ≅ BD

Both the triangles will be congruent.

Therefore, additional information required to prove ΔABC ≅ ΔDBC have been given in option (1).

Therefore, Option (1) will be the answer.

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1 year ago

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Consider the diagram.<br> What is QS?<br> 2 units<br> 5 units<br> 17 units<br> 33 units

blagie [28]

Answer:

The answer on ed is 17 units I took the test.

Step-by-step explanation:

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2 years ago

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Drag and drop an answer to each box to correctly complete the explanation for deriving the formula for the volume of a sphere.

Advocard [28]

The volume of a sphere is given by:

$V= \frac{4}{3} \pi r^{3}$

So, we need to deduct this equation. We will walk through Calculus on the concept of a solid of revolution that is a solid figure that is obtained by rotating a plane curve around some straight line (the axis of revolution<span>) that lies on the same plane. We know from calculus that:

</span> $V=\pi \int_{a}^{b}[f(x)]^{2}dx$
<span>
Then, according to the concept of solid of revolution we are going to rotate a circumference shown in the figure, then:

</span> $x^{2}+y^{2}=r^{2}$
<span>
Isolationg y:

</span> $y= \sqrt{r^{2}-x^{2}}$ <span>

So,

</span> $f(x)=y=\sqrt{r^{2}-x^{2}}$ <span>

</span> $V=\pi \int_{a}^{b}[\sqrt{r^{2}-x^{2}}]^{2}dx$
<span>
</span> $V=\pi \int_{a}^{b}(r^{2}-x^{2})dx$ <span>

being -r and r the limits of this integral.

</span> $V=\pi \int_{-r}^{r}(r^{2}-x^{2})dx$
<span>
Solving:

</span> $V=\pi[r^{2}x-\frac{x^{3}}{3}]\right|_{-r}^{r}$

Finally:
<span>
</span> $V=\pi(r^{3}-\frac{r^{3}}{3})-\pi(-r^{3}+\frac{r^{3}}{3})= \frac{4}{3} \pi r^{3}$ <span>
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1 year ago

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Round 96.9617186007 to the nearest tenth.

Pavlova-9 [17]

if you're talking about the whole number, 100.96. if you're referring to decimal place values; 96.70.

underline the digit that you round to

circle the digit to the right

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everything behind becomes a zero.

6 0

2 years ago

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Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

(a)

The bid should be greater than $10,000 to get accepted by the seller. Let bid x be a continuous random variable that is uniformly distributed between

$10,000 and $15,000

The interval of the accepted bidding is $[ {\rm{\$ 10,000 , \$ 15,000}]$ , where b = $15000 and a = $10000.

The interval of the provided bidding is [$10,000,$12,000]. The probability is calculated as,

$\begin{array}{c}\\P\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{12000}^{15000}\\\end{array}$

$=1- \frac{[15000-12000]}{5000}\\\\=1-0.6\\\\=0.4$

(b) The interval of the accepted bidding is [$10,000,$15,000], where b = $15,000 and a =$10,000. The interval of the given bidding is [$10,000,$14,000].

$\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)$

$=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8$

(c)

The amount that the customer bid to maximize the probability that the customer is getting the property is calculated as,

The interval of the accepted bidding is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The interval of the given bidding is [$10,000,$15,000].

$\begin{array}{c}\\f\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\\\\{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\\\\{\rm{ = 1}}\\\end{array}$

(d) The amount that the customer bid to maximize the probability that the customer is getting the property is $15,000, set by the seller. Another customer is willing to buy the property at $16,000.The bidding less than $16,000 getting considered as the minimum amount to get the property is $10,000.

The bidding amount less than $16,000 considered by the customers as the minimum amount to get the property is $10,000, and greater than $16,000 will depend on how useful the property is for the customer.

5 0

2 years ago