Megan went clothes shopping and bought 2 pairs of flare jeans, 2 camisoles, and 4 t-shirts for $90.00. at the same store, paige
bought one pair of flare jeans and 3 t-shirts for $42.50, while kara bought 1 pair of flare jeans, 3 camisoles, and 2 t-shirts for $62.00. determine the price of each clothing item.
1 answer:
If you let j, c, t represent the prices of jeans, camisoles, and t-shirts, respectively, the three purchases can be described by ...
2j +2c +4t = 90.00
1j +0c +3t = 42.50
1j +3c +2t = 62.00
It is convenient to let a calculator solve these equations. It can tell you the row-reduced matrix equations are ...
[[1 0 0 24.5]
[0 1 0 8.5 ]
[0 0 1 6 ]]
which means
flare jeans cost $24.50
camisoles cost $8.50
T-shirts cost $6.00
2j +2c +4t = 90.00
1j +0c +3t = 42.50
1j +3c +2t = 62.00
It is convenient to let a calculator solve these equations. It can tell you the row-reduced matrix equations are ...
[[1 0 0 24.5]
[0 1 0 8.5 ]
[0 0 1 6 ]]
which means
flare jeans cost $24.50
camisoles cost $8.50
T-shirts cost $6.00
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Answer:
(a) The probability that of the 5 eggs selected exactly 5 are unspoiled is 0.0531.
(b) The probability that of the 5 eggs selected 2 or less are unspoiled is 0.3959.
(c) The probability that of the 5 eggs selected more than 1 are unspoiled is 0.8747.
Step-by-step explanation:
The complete question is:
A really bad carton of 18 eggs contains 8 spoiled eggs. An unsuspecting chef picks 5 eggs at random for his “Mega-Omelet Surprise.” Find the probability that the number of unspoiled eggs among the 5 selected is
(a) exactly 5
(b) 2 or fewer
(c) more than 1.
Let <em>X</em> = number of unspoiled eggs in the bad carton of eggs.
Of the 18 eggs in the bad carton of eggs, 8 were spoiled eggs.
The probability of selecting an unspoiled egg is:
A randomly selected egg is unspoiled or not is independent of the others.
It is provided that a chef picks 5 eggs at random.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.556.
The success is defined as the selection of an unspoiled egg.
The probability mass function of <em>X</em> is given by:
(a)
Compute the probability that of the 5 eggs selected exactly 5 are unspoiled as follows:
Thus, the probability that of the 5 eggs selected exactly 5 are unspoiled is 0.0531.
(b)
Compute the probability that of the 5 eggs selected 2 or less are unspoiled as follows:
P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)
Thus, the probability that of the 5 eggs selected 2 or less are unspoiled is 0.3959.
(c)
Compute the probability that of the 5 eggs selected more than 1 are unspoiled as follows:
P (X > 1) = 1 - P (X ≤ 1)
= 1 - P (X = 0) - P (X = 1)
Thus, the probability that of the 5 eggs selected more than 1 are unspoiled is 0.8747.