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2 years ago

3

Jonathan and Tim want to predict how many quarters are in a large jar containing 120 coins. Jonathan randomly selects a sample o

f 10 coins from the jar, while Tim randomly selects a sample of 30 coins. Then they count the number of quarters in each sample. Whose sample should more accurately predict the number of quarters in the jar?
who's sample should give a more accurate prediction of the number of quarters in the jar Jonathan's or Tim's

2 answers:

pashok25 [27]2 years ago

4 0

Jonathan’s because there are less coins than thirty which gives it less number of spots for quarters

egoroff_w [7]2 years ago

4 0

i do not agree with him

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Given a circle described by the equation:
$y^2+x^2=100$
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$\begin{center}
\begin{tabular}{ |c |c |c }
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The function g(x) describes a straight line with the equation:
$\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1} \\ \\ \frac{y-(-22)}{x-(-1)} = \frac{-20-(-22)}{0-(-1)} \\ \\ \frac{y+22}{x+1} = \frac{-20+22}{0+1} = \frac{2}{1} \\ \\ y+22=2(x+1)=2x+2 \\ \\ y=2x-20$

To check if the circle and the line intersects, we substitute the equation of the line into the equation of the circle to see if we have a real solution.
i.e.
$y^2+x^2=100 \\ \\ (2x-20)^2+x^2=100 \\ \\ 4x^2-80x+400+x^2=100 \\ \\ 5x^2-80x+300=0 \\ \\ x^2-16x+60=0 \\ \\ (x-6)(x-10)=0 \\ \\ x-6=0 \ or \ x-10=0 \\ \\ x=6 \ or \ x=10$

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Therefore, the circle and the line intersect at the points (6, -8) and (10, 0).

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sergij07 [2.7K]

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Anarel [89]

Answer: The frog fell asleep for 4 nights.

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In 154 N38 what digit should be replaced to N to make the number divisible by 3,6 and 9?

JulsSmile [24]

Answer:

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Step-by-step explanation:

In Number Theory there is a rule of thumb which states that sum of digits of a multiple of 3 equal 3 or a multiple of three. If we know that $n = 154N38$ , then its sum of digits is:

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We have to determine which digits corresponds to multiples of three, there are four digits:

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N = 3

$x = 21+3$

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$x = 21+6$

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N = 9

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We get the following four distinct options: 154038, 154338, 154638, 154938. Now we find which number is divisible by 6 and 9 by factor decomposition:

$154038 = 2\times 3\times 25673$

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$154638 = 2\times 3\times 3\times 11\times 11\times 71$

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It is quite evident that $N = 6$ so that number becomes divisible by 3, 6 and 9.

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