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ira [324]
2 years ago
4

Many species of chemosynthetic bacteria have evolved symbiotic relationships with other organisms. For example, chemosynthetic b

acteria can be found in the bodies of tube worms that live near hydrothermal vents. Although tube worms cannot produce their own food, they often thrive around these underwater vents. How are the tube worms able to survive? A. Tube worms feed on glucose produced by the chemosynthetic bacteria they harbor. B. Tube worms feed on inorganic compounds produced by the chemosynthetic bacteria they harbor. C. Tube worms digest chemosynthetic bacteria to obtain glucose. D. Tube worms digest chemosynthetic bacteria to obtain inorganic compounds.
Mathematics
1 answer:
vichka [17]2 years ago
3 0
The answer is t<span>ube worms feed on (glucose )produced the type of chemosynthetic bacteria they harbor. thanks brainly</span>
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Javier works each weekend at an animal shelter. He earns $8 an hour. He is saving his earnings to go on a ski trip that costs $1
Harman [31]

Answer:

Step-by-step explanation:

She earns $8/hour

And she works weekend only

He is saving his earning to go for ski and it cost $190

For him to save $190, let know the hours he is going to work

He earns $8/hour and need $190,

Then he is going to work for

190/8=23.75hours

At least, he needs to work for 24hours and since the 24hours is in a day then, Becca his wrong, he doesn't need extra to work extra 6hours.

We are not told if he need to buy something or do something else we are only told he needs $190 for the trip

4 0
2 years ago
An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do
vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107

Then,

P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007

c) In this case, the distribution is B(1200,0.01)

P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366

5 0
2 years ago
TV−→− bisects ∠RTS. If the m∠RTV=(16x−6)° and m∠VTS=(13x+9)° , what is the value of x and the m∠RTV ?
natta225 [31]

Answer:

x = 5

RTV = 74

Step-by-step explanation:

Given

RTV=16x - 6

VTS=13x+9

Required

Determine the values of x and RTV

Since, TV is a bisector, then

RTS = RTV + VTS --- (1)

and

RTV = VTS -- (2)

Substitute values of RTV and VTS in (2)

16x - 6 = 13x + 9

Collect Like Terms

16x - 13x = 9 + 6

3x = 15

Solve for x

x = 5

Substitute 5 for x in RTV=16x - 6

RTV = 16 * 5 - 6

RTV = 80 - 6

RTV = 74

8 0
2 years ago
There are 1,000 golden delicious and 1,000 red delicious apples in a cooler. In a random sample of 75 of the golden delicious ap
Delvig [45]

Answer:

98% confidence interval is (-0.105 , 0.265)

Step-by-step explanation:

n1 = 75          n2 = 75

X1 = 48          X2 = 42

P1 = X1/N1 = 0.64          P2 = X2/N2   = 0.56

98% confidence interval for difference between two proportions is :

P1 - P2  <u>+</u>   Z \sqrt{P1 (1-P1)/n1  + P2 (1-P2)/n1}

= 0.08 <u>+</u> 0.185

= (-0.105 , 0.265)

98% confidence interval is (-0.105 , 0.265)

4 0
2 years ago
A city distributes vehicle identification stickers using a combination of letters followed by a combination of​ digits, each of
gayaneshka [121]
A) 672750
B) 68250
C) 2960100

Explanation
A)  We have 26 letters from which to choose 4, and 10 digits from which to choose 2:
_{26}C_4\times_{10}C_2=\frac{26!}{4!22!}\times\frac{10!}{2!8!}=14950\times45=672750

B) We have 26 letters from which to choose 2, and 10 digits from which to choose 4:
_{26}C_2\times_{10}C_4=\frac{26!}{2!24!}\times\frac{10!}{4!6!}=325\times210=68250

C) We have 26 letters from which to choose 5, and 10 digits from which to choose 2:
_{26}C_5\times_{10}C_2=\frac{26!}{5!21!}\times\frac{10!}{2!8!}=65780\times45=2960100
5 0
2 years ago
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