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Lelu [443]
2 years ago
5

The standard cell potential (e°cell) of the reaction below is +1.34 v. the value of δg° for the reaction is ________ kj/mol. 3 c

u (s) + 2 mno4 - (aq) + 8h+ (aq) → 3 cu2+ (aq) + 2 mno2 (s) + 4 h2o (l)
Chemistry
1 answer:
Pani-rosa [81]2 years ago
5 0
E°cell =+1.34V
F= 96485C mol-1
3Cu(s) →3CU2+(aq) +6e-E°ck= -0.34V
2MnO4-(aq) +8H+(aq)+6e→2MnO2(s)+4H2O(l)/3CU(s) + 2MnO4-(aq)+8H+(aq)→3CU 2+((aq)+ 2MnO2(s)+4H2O (l) 
E°red= +1.68V/E°cell=+1.34V
ΔG° = -nFE°cell = -6×96485×1.34 = -775.7kJ/mol
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Carbon dating of small bits of charcoal used in cave paintings has determined that some of the paintings are from 10000 to 30000
Andru [333]

The age of painting was determined from the decay kinetics of the radioactive Carbon -14 present in the painting sample.

Given that the half life of Carbon-14 is 5730 years.

Radioactive decay reactions follow first order rate kinetics.

Calculating the decay constant from half life:

λ= \frac{0.693}{t_{1/2} }

        = \frac{0.693}{5730 yr} = 1.21*10^{-4}yr^{-1}

Setting up the radioactive rate equation:

ln\frac{A_{t} }{A_{0} } =-kt

Where A_{t} = Activity after time t = 0.80microCi

A_{t} = initial activity = 6.4microCi

k = decay constant = 1.21*10^{-4}yr^{-1}

ln\frac{0.80uCi}{6.4uCi} =-(1.21*10^{-4}yr^{-1})t

ln 0.125 = -(1.21*10^{-4}yr^{-1})t

-2.079=-(1.21*10^{-4}yr^{-1})t

t=\frac{2.07944}{1.21*10^{-4} } yr

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t = 17185 years

Therefore age of the painting based in the radiocarbon -14 dating studies is 17185 years



6 0
2 years ago
Write equation for the first ionization energy of neon. express your answer as a chemical equation. identify all of the phases i
Montano1993 [528]

The first ionization energy of a known element is the energy it needs to remove its highest energy or outermost electron. It is done to make a neutral atom be a positively charged ion. The first ionization energy of neon as a chemical equation is this:

Ne (g) -> Ne+ (g) + e-

 

8 0
2 years ago
A 100-W lightbulb is placed in a cylinder equipped with a moveable piston. The lightbulb is turned on for 0.020 h, and the assem
nasty-shy [4]

Answer: The workdone W = 505J

Explanation:

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W= - PΔV

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= - 1.0atm * (4.98)

W = -4.98 atmL

Converting to Joules

1atmL = 101.325J

-4.98atmL = x joules.

Work done in J = -4.98 * 101.325

W= -505J

Therefore the workdone is -505J

5 0
2 years ago
What alkene reacts the fastest with HBr?
Rasek [7]
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<span>So to solve your problem, protonate all your Alkenes following Markovnikov's rule, and then compare the relative stability of your resulting carbocations. Tertiary is more stable than secondary, so an Alkene that produces a tertiary carbocation reacts faster than an Alkene that produces a secondary carbocation.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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3 0
2 years ago
Read 2 more answers
In the chemical equation 3c2h4 how many atoms of carbon are represented
Scorpion4ik [409]
An example.
water is H2O

2 hydrogen, 1 oxygen

so the number to the right means how much of what is on the left.

so it looks like 2, because C2, but look at the 3 at the beginning. that means
3 (c2h4)

so 6 carbons, 12 hydrogen

the ratio of c2 to h4 doesn't change it's always 1:2.

but the 3 at the front is a different number relating to how much you have
5 0
2 years ago
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