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Nadusha1986 [10]
2 years ago
15

Hydroxyl radicals react with and eliminate many atmospheric pollutants. However, the hydroxyl radical does not clean up everythi

ng. For example, chlorofluorocarbons - which destroy stratospheric ozone - are not attacked by the hydroxyl radical. Consider the hypothetical reaction by which the hydroxyl radical might react with a chlorofluorocarbon: OH(g)+CF2Cl2(g)-->HOF(g)+CFCl2(g)Use bond energies to explain why this reaction is improbable. Calculate \Delta Hrxn of this reaction.
Chemistry
1 answer:
Nesterboy [21]2 years ago
7 0

Answer:

ΔHreaction = 263.15 kJ/mol

Explanation:

The reaction is as follow:

OH + CF₂Cl₂ → HOF + CFCl₂

You need to calculate the enthalpy of reaction and for this it is necessary to know the standard enthalpies for each of the compounds. These enthalpies are as follows and can be found in your textbook or on the Internet.

ΔHreaction = ∑ΔHproducts - ∑ΔHreactants

delta(H)_{reaction} =((1*(-97.8)+(1*(-92))-((1*39)+(1*(-491.15))=263.15kJ/mol

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2 years ago
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Pepsi [2]

Answer:

Mass_{chromium}=52.1\ g

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Explanation:

<u>Calculation of the mass of chromium as:- </u>

Moles = 1.002 moles

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The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

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Mass_{neon}=4.08\times 10^{-8}\times 20.1797\ g = 8.23\times 10^{-7}\ g

6 0
2 years ago
Why couldn't you substitute 3m H2SO4 for concentrated HNO3 when oxidizing copper?
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This question seems to be an essay question from experiment. Different solution of oxidizing agent will have different strength.  Sulfuric acid or H2SO4 is weaker oxidizing agent when compared to nitric acid (HNO3). In this case, if you subtitute the H2SO4 you wouldn't be able to get the same result for the experiment.



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2 years ago
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X + Y XY + heat What happens as the temperature is increased?
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If the frequency of a radio station is 88.1 MHz (8.81 × 107 Hz), what is the wavelength of the wave used by this radio station f
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Hello!

If the frequency of a radio station is 88.1 MHz, the wavelength of the wave used by this radio station for its broadcast is 3.403 m

<h2>Why?</h2>

We are going to use the following equation that shows the relation of the frequency of a wave with its wavelength, knowing that radio waves are electromagnetic waves and they travel at the speed of light (299 792 458 m/s):

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