All categories

2 years ago

What is the total mass of a mixture of 3.50x10^22 formula units na2so4, 0.500 mol h2o, and 7.23 g agcl?

1 answer:

5 0

Answer is: mass of the mixture is 24,47 g.
1) N(Na₂SO₄) = 3,5·10²².
n(Na₂SO₄) = 3,5·10²² ÷ 6·10²³ 1/mol.
n(Na₂SO₄) = 0,058 mol.
m(Na₂SO₄) = 0,058 mol · 142 g/mol.
m(Na₂SO₄) = 8,24 g.
2) n(H₂O) = 0,500 mol.
m(H₂O) = 0,5 mol · 18 g/mol.
m(H₂O) = 9 g.
3) m(total) = 8,24 g + 9 g + 7,23 g.
m(total) = 24,47 g.
n - amount of substance.

You might be interested in

What is the theoretical yield of CuS when 31.8g of Cu(s) is heated with 50.0g of S? (Asume only CuS is produced in the reaction)

liberstina [14]

Answer:

The answer to your question is: 83.9 %

Explanation:

Data

Cu = 31.8 g

S = 50 g

CuS = 40 g

yield = ?

Equation

Cu + S ⇒ CuS

MW Cu = 64 g

MW S = 32 g

MW CuS = 96 g

Ratio (theoretical/experimental)

Experimental 50/31.8 = 1.57

Theoretical 32/64 = 0.5 limiting reactant Cu

64 g of Cu ------------------ 96 g of CuS

31.8 g ------------------- x

x = (31.8 x 96) / 64

x = 47.7 g of CuS

% yield = (40/47.7) x 100

= 83.9 %

6 0

2 years ago

Read 2 more answers

You are performing an experiment in your lab. To compare with other experiments you need your results to be in moles. During you

lys-0071 [83]

To be able to compare the result with other experiments it has to be reported in moles.

number of moles = mass / molecular weight

number of moles of Mg(H₂PO₄)₂ = 600 / 218 = 2.75 moles

7 0

2 years ago

Read 2 more answers

What is the pH of a solution prepared by mixing 50.00 mL of 0.10 M methylamine, CH3NH2, with 20.00 mL of 0.10 M methylammonium c

olya-2409 [2.1K]

Answer:

pH=10.97

Explanation:

the solution of methyl amine with methylammonium chloride will make a buffer solution.

The pH of buffer solution can be obtained using Henderson Hassalbalch's equation, which is:

$pOH=pKb+log\frac{[salt]}{[base]}$

pH = 14- pOH

Let us calculate pOH $pOH=3.43+ (-0.397)=3.03$

$pH=14-pOH=14-3.03=10.97$

[Salt] = [methylammonium chloride] = 0.10 M (initial)

After adding base

$[salt] = \frac{molarityXvolume}{finalvolume}=\frac{0.1X20}{(20+50)}= 0.0286M$

[base] = [Methylamine]=0.10

After mixing with salt

$[base]= \frac{molarityXvolume}{finalvolume}=\frac{0.1X50}{(20+50)}= 0.0714M$

pKb= -log[Kb]= 3.43

Putting values

pOH = $3.43+log(\frac{[0.0286]}{0.0714}$

4 0

2 years ago

Question 4: Which members of an ecosystem are part of the energy flow?

Vanyuwa [196]

Answer:

The answer is A (number 1)

5 0

2 years ago

How many hydrogen bonds can CH2O make to water

VladimirAG [237]

Hydrogen bonds are not like covalent bonds. They are nowhere near as strong and you can't think of them in terms of a definite number like a valence. Polar molecules interact with each other and hydrogen bonds are an example of this where the interaction is especially strong. In your example you could represent it like this:

H2C=O---------H-OH 

But you should remember that the H2O molecule will be exchanging constantly with others in the solvation shell of the formaldehyde molecule and these in turn will be exchanging with other H2O molecules in the bulk solution. 

Formaldehyde in aqueous solution is in equilibrium with its hydrate. 

H2C=O + H2O <-----------------> H2C(OH)2

5 0

2 years ago