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Nastasia [14]
2 years ago
13

If the frequency of a radio station is 88.1 MHz (8.81 × 107 Hz), what is the wavelength of the wave used by this radio station f

or its broadcast? The answer should have three significant figures.
Chemistry
2 answers:
Grace [21]2 years ago
5 0

Hello!

If the frequency of a radio station is 88.1 MHz, the wavelength of the wave used by this radio station for its broadcast is 3.403 m

<h2>Why?</h2>

We are going to use the following equation that shows the relation of the frequency of a wave with its wavelength, knowing that radio waves are electromagnetic waves and they travel at the speed of light (299 792 458 m/s):

Wavelength=\frac{Speed_{Light}}{Frequency}= \frac{299 792 458 m/s}{8.81*10^{7} Hz}=3.402865\approx3.403 m

Have a nice day!

wlad13 [49]2 years ago
5 0

The answer is 3.41 meters

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Cyclohexane has a freezing point of 6.50 ∘C and a Kf of 20.0 ∘C/m. What is the freezing point of a solution made by dissolving 0
ExtremeBDS [4]

Answer:

The freezing point will be 2.9^{0}C

Explanation:

The depression in freezing point is a colligative property.

It is related to molality as:

Depressioninfreezing point=K_{f}Xmolality

Where

Kf= 20\frac{^{0}C}{m}

the molality is calculated as:

molality=\frac{moles_{solute}}{mass_{solvent}}

moles=\frac{mass}{molarmass}=\frac{0.694}{154}=0.0045mol

massofcyclohexane=25g=0.025Kg

molarity=\frac{0.0045}{0.025}=0.18m

Depression in freezing point = 20X0.18=3.6^{0}C

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2 years ago
The pH of an aqueous solution is 4.32. What is the [OH–]?
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2.10 x 10^-10 M. Ans


pH + pOH = 14
Where, pOH is the power of hydroxide ion concentration and pH is the power of concetration of the H+ ion.
Now, pOH = 14 - 4.32
= 9.68
Now, the concentration of [H+] is 10-7 M, then pH is 7 and for [OH-] = 10-7 M, the pOH is also 7.

Now, pOH = -log[OH-]
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8 0
2 years ago
2. If 2.50g of sodium hydroxide is being reacted with 4.30g of magnesium chloride, how many grams of magnesium hydroxide would b
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Answer:

1.822 g of magnesium hydroxide would be produced.

Explanation:

Balanced reaction: 2NaOH+MgCl_{2}\rightarrow Mg(OH)_{2}+2NaCl

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         NaOH                                           39.997

         MgCl_{2}                                           95.211

        Mg(OH)_{2}                                        58.3197

So, 2.50 g of NaOH = \frac{2.50}{39.997} mol of NaOH = 0.0625 mol of NaOH

      4.30 g of MgCl_{2}  = \frac{4.30}{95.211} mol of MgCl_{2} = 0.0452 mol of MgCl_{2}

According to balanced equation-

2 mol of NaOH produce 1 mol of Mg(OH)_{2}    

So, 0.0625 mol of NaOH produce (\frac{0.0625}{2}) mol of NaOH or 0.03125 mol of NaOH

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So, 0.0452 mol of MgCl_{2} produce 0.0452 mol of Mg(OH)_{2}

As least number of moles of Mg(OH)_{2} are produced from NaOH therefore NaOH is the limiting reagent.

So, amount of Mg(OH)_{2} would be produced = 0.03125 mol

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                                                                           = 1.822 g

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Explanation:

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Answer: The questions looks unclear

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