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krek1111 [17]
2 years ago
8

Sarah goes to her local pizza parlor and orders a pizza. She can choose either a large or a medium pizza, has a choice of one of

seven diffrent toppings (extra cheese, pepperoni, sausage, beef, green pepper, onion, mushroom) and can have three different choices of crust (thin, regular, pan). How many different pizzas could Sarah order?
Mathematics
2 answers:
mariarad [96]2 years ago
8 0
She could order 42 different pizzas
Thepotemich [5.8K]2 years ago
7 0
2 sizes, 7 toppings and 3 crusts

multiply the choices together:

2 * 7 * 3 = 42 different pizzas
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First part of the race

speed1, s1 = 8.75 km/h
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s2 = x/t = 6 ⇒ t = x / 6

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5 - x = 8.75 [0.65 - t]

5 -x = 8.75(0.65) - 8.75t

5 - x = 5.6875 - 8.75 (x/6)

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Here, Convenience sampling is used by the poll

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A website manager has noticed that during the evening​ hours, about 3.23.2 people per minute check out from their shopping cart
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Answer:

1.  c. Poisson

2. 0.9592 = 95.92% probability that in any one minute at least one purchase is​ made.

3. 0.0017 = 0.17% probability that no one makes a purchase in the next 2​ minutes.

Step-by-step explanation:

We have only the mean, which means that the Poisson distribution is used to solve this question, and thus the answer to question 1 is given by option c.

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In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

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In which

x is the number of sucesses

e = 2.71828 is the Euler number

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Mean of 3.2 minutes:

This means that \mu = 3.2n, in which n is the number of minutes.

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n = 1, so \mu = 3.2.

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3. What is the probability that no one makes a purchase in the next 2​ minutes?

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This probability is P(X = 0). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-6.4}*6.4^{0}}{(0)!} = 0.0017

0.0017 = 0.17% probability that no one makes a purchase in the next 2​ minutes.

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2 years ago
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