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Lerok [7]
2 years ago
13

Priya is playing a game where she earns online badges for scoring higher than the mean score on a level. After the tenth level,

she scores 3,540 points, which is 2 standard deviations above the mean score of 3,110 points.
What is the standard deviation of scores for the tenth level?

a.)215
b.)311
c.)354
d.)430
Mathematics
2 answers:
Lisa [10]2 years ago
4 0

Answer: Option 1(A)

Got it right on ED, Good luck!! :)

Vlad [161]2 years ago
3 0
If score of 3,540 points is 2 standard deviations above the mean score of 3,110, then:
3,110 + 2 s= 3,540
2 s = 3,540 - 3,110 = 430
s = 430 : 2
s = 215
Answer: A) The standard deviation is 215. 
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A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
2 years ago
What is the sum of 3/2x and 7/4x
Advocard [28]


3/2x +7/4x = ...........

3/2x(4/4)+7/4x(2/2)

12/8x+14/8x = 26/8x

26/8x = 13/4x(3.25x)  

4 0
2 years ago
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A lotion is made from an oil blend costing $1.50 per ounce and glycerin costing $1.00 per ounce. Four ounces of lotion costs $5.
Svet_ta [14]

Answer:

A (4-g)1.5

Step-by-step explanation:

hope this helps if you need a explanation just ask in the comments and I will.

8 0
2 years ago
The table below shows the amount of lemon juice and sugar needed to make three different-sized batches of lemonade using the sam
mash [69]

Answer:

<u>j = 2.5s</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

                Lemon juice (mL)      Sugar (gr)

Batch A        500                             200

Batch B         750                             300

Batch C       1,500                             600

2. Write an equation to describe the relationship between j, the amount of lemon juice in mL, and s, the amount of sugar in g.

Ratio = Amount of lemon juice/Amount of sugar

Ratio = 500/200 = 750/300 = 1,500/600

Ratio = 2.5

Now, we can write the equation, this way:

<u>j = 2.5s</u>

8 0
2 years ago
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19x+rx=-37+w <br><br><br> solve for x
ipn [44]

Factor the left side:-

x (19 + r) = -37 + w

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2 years ago
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