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grandymaker [24]
2 years ago
9

Based on the crystal-field strengths cl- < f- < h2o < nh3 < h2nc2h4nh2, which octahedral ti (iii) complex below has

its d-d electronic transition at shortest wavelength?
Chemistry
1 answer:
kati45 [8]2 years ago
8 0
<span>Based on the crystal field strength, Cl ligand would give the longest d-d transition when complexed with Ti(III). as this is the weak field ligand and would cause minimum splitting of d orbitals.</span>
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Write the net ionic equation for the reaction of zinc metal with aqueous iron(II) nitrate. Include physical states.
kotykmax [81]

Answer:

Zn°(s) + Fe⁺²(aq)  => Zn⁺²(aq) + Fe°(s)

Explanation:

Molecular Equation:

Zn°(s) + Fe(NO₃)₂(aq) => Zn(NO₃)₂(aq) + Fe°(s)

Ionic Equation:

Zn°(s) + Fe⁺²(aq) + 2NO₃⁻(aq) => Zn⁺²(aq) + 2NO₃⁻(aq) + Fe°(s)

Net Ionic Equation: => Drop NO₃⁻ as spectator ion

Zn°(s) + Fe⁺²(aq)  => Zn⁺²(aq) + Fe°(s)

7 0
2 years ago
If the lead can be extracted with 92.5% efficiency, what mass of ore is required to make a lead sphere with a 3.50 cm radius? le
ElenaW [278]

The volume of sphere can be calculated using the following formula:


V=\frac{4}{3}\pi r^{3}


Here, r is radius of the sphere which is 3.5 cm. Putting the value,


V=\frac{4}{3}\pi r^{3}=\frac{4}{3}(3.14)(3.5cm)^{3}=180 cm^{3}


This is equal to the volume of lead, density of lead is 11.34 g/cm^{3} thus, mass of lead can be calculated as follows:


m=d×V


Putting the values,


m=11.34 g/cm^{3}\times 180 cm^{3}=2041.2 g


Let the mass of ore be 1 g, 68.6% of galena is obtained by mass, thus, mass of galena obtained will be 0.686 g.


Now, 86.6% of lead is obtained from this gram of galena, thus, mass of lead will be:


m=0.686×0.866=0.5940 g


Therefore, 0.5940 g of lead is obtained from 1 g of ore for 100% efficiency, thus, for 92.5% efficiency

m=\frac{92.5}{100}\times 0.5940=0.54945 g

1 g of lead obtain from\frac{1}{0.54945}=1.82 grams of ore.


Thus, 2041.2 g of lead obtain from:


2041.2\times 1.82=3.715\times 10^{3}g or 3.715 kg


Therefore, mass of ore required to make lead sphere is 3.715 kg.


6 0
2 years ago
A sample of gasoline contains various hydrocarbons, which comprise atoms of carbon, hydrogen, and oxygen. The hydrocarbons mix t
Naddika [18.5K]

Answer:

  • mixture
  • homogenous mixture  (of hydrocarbons)
  • compound

Explanation:

Mixture can be easily separated by physical methods. Homogeneity and heterogeneity of a mixture is determined by whether the components there in are in a single phase and evenly distributed or not.

A solution has a solute evenly dissolved in  solvent to form a liquid substance.

An element is the basic form of  substance which cannot be broke down into any other simpler unit.  

I hope this was helpful.

4 0
2 years ago
Valproic acid, used to treat seizures and bipolar disorder, is composed of C, H, and O. A 0.165-g sample is combusted to produce
sergeinik [125]

Answer:

The empirical formula is = C_4H_8O

The formula of Valproic acid = C_8H_{16}O_2

Explanation:

Mass of water obtained = 0.166 g

Molar mass of water = 18 g/mol

Moles of H_2O = 0.166 g /18 g/mol = 0.00922 moles

2 moles of hydrogen atoms are present in 1 mole of water. So,

<u>Moles of H = 2 x 0.00922 = 0.01844 moles </u>

Molar mass of H atom = 1.008 g/mol

<u>Mass of H in molecule = 0.01844 x 1.008 = 0.018588 g </u>

Mass of carbon dioxide obtained = 0.403 g

Molar mass of carbon dioxide = 44.01 g/mol

Moles of CO_2 = 0.403 g  /44.01 g/mol = 0.009157 moles

1 mole of carbon atoms are present in 1 mole of carbon dioxide. So,

<u>Moles of C = 0.009157 moles </u>

Molar mass of C atom = 12.0107 g/mol

<u>Mass of C in molecule = 0.009157 x 12.0107 = 0.11 g </u>

<u>Given that the Valproic acid only contains hydrogen, oxygen and carbon. </u>So,

Mass of O in the sample = Total mass - Mass of C  - Mass of H

Mass of the sample = 0.165 g

<u>Mass of O in sample = 0.165 - 0.11 - 0.018588 = 0.036412 g  </u>

Molar mass of O = 15.999 g/mol

<u>Moles of O  = 0.036412  / 15.999  = 0.002276 moles</u>

<u></u>

<u>Taking the simplest ratio for H, O and C as: </u>

<u>0.01844 : 0.002276 : 0.009157</u>

<u> = 8 : 1 : 4</u>

The empirical formula is = C_4H_8O

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 4×12 + 8×1 + 16= 72 g/mol

Molar mass = 144 g/mol

So,  

Molecular mass = n × Empirical mass

144 = n × 72

<u>⇒ n = 2</u>

The formula of Valproic acid = C_8H_{16}O_2

7 0
2 years ago
If you find that the hydrogen alpha line in a star’s spectrum occurs at a wavelength of 656.45 nm, what is the star’s approximat
Paladinen [302]

Answer:

The answer to the question is

The star’s approximate radial velocity is 68.52 km/s

Explanation:

To solve the

The formula is

\frac{\lambda-\lambda_{rw}}{\lambda_{rw}} = \frac{v_r}{c} where

v_r = velocity of the star

λ = Star's spectrum wavelength = 656.45 nm

\lambda_{rw} = Rest wavelength = 656.30 nm

c = Speed of light = 299 792 458 m / s

Therefore we have

\frac{656.45-656.30}{656.30} =\frac{v_r}{299 792 458} or v_r = 68518.7699 m/s or 68.52 km/s

8 0
2 years ago
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