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lorasvet [3.4K]
2 years ago
7

If the total income generated from gasoline for AER was $408 million how much would be the cost for a barrel of gasoline, gasoli

ne 34% kerosene 14% 60 million barrels total production crude oil
Mathematics
2 answers:
Rzqust [24]2 years ago
4 0

The correct answer is: $20

Explanation:

As we are interested in finding the cost for a barrel of gasoline, we need to read the percentage of gasoline from the pie-chart first—which is 34%.

Now number of barrels containing gasoline = 34% of 60 million barrels = \frac{34}{100} * 60 = 20.4 million barrels

For all the barrels, the total income is $408 million; therefore, in order to find the per-barrel cost, we need to divide $408 by 20.4:

\frac{408}{20.4} = \$20

Hence the correct answer is $20.

Mazyrski [523]2 years ago
3 0
The problem statement appears to be trying to tell you that 60 million barrels of crude were processed, resulting in 34% of that volume being turned into gasoline, which was then sold for a total of $408 million. You are asked for the revenue associated with 1 barrel of gasoline.

($408·10^6)/(60·10^6 bbl × 0.34) = $408/(20.4 bbl) = $20/bbl

The income from one barrel of gasoline is $20.00.
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Answer:

Step-by-step explanation:

600 X .50 = 300.00 1st month

600 X .05 = 30.00 47 months

30 X 47 = 1,410

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The correct answer is 40 bars. 

In order to find this amount we have to find when the y values are worth the same. Since both equations are equal to y, we can set them equal to each other to find a time when the y values are the same. 

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Keith_Richards [23]

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a

Step-by-step explanation:

8 0
2 years ago
If mJI = (3x+2)°, mHLK = (15x-36)°, and m∠HML = (8x-1)°, find mHLK
Gala2k [10]

Answer:

The value of mHLK will be "(204)°".

Step-by-step explanation:

The given values are:

mJI = (3x+2)°

mHLK = (15x-36)°

and,

m∠HML = (8x-1)°

then,

mHLK = ?

Now,

By using chord-chord formula of angle, we get

mHMK=\frac{1}{2}(mJL+mHLK)

On putting the values in the above formula, we get

⇒  (8x-1)=\frac{1}{2}(15x-36+3x+2)

On applying cross-multiplication, we get

⇒  2(8x-1)=18x-34

⇒  16x-2=18x-34

On subtracting "18x" from both sides, we get

⇒  16x-2-18x=18x-34-18x

⇒  -2x-2=-34

On adding "2" both sides, we get

⇒  -2x=-34+2

⇒  -2x=-32

⇒  x=\frac{32}{2}

⇒  x=16

On putting the value of "x" in mHLK = (15x-36)°, we get

⇒ (15x-36)° = (15×16-36)°

⇒                = (240-36)°

⇒                = (204)°

So that mHLK = (204)°

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