Thanksgiving
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Hello there,
There is a total of 40 animals in that in 10 zebras, 10 lions, 10 elephants, and 10 monkeys.
So the probability of them both being lions is pretty rare. 2/40 so that would give you a 1/20 chance of both crackers being both lions.
I hope this helps!
Answer:
B is the answer.
Step-by-step explanation:
![x^{\frac{m}{n} } = \sqrt[n]{x^{m} }](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%20%7D%20%20%3D%20%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%20%7D)
![\sqrt[4]{81^{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B81%5E%7B5%7D%20%7D)
= 
Answer: B) 18
Step-by-step explanation:
The degree of freedom for Standard error or df(Residual) is the sample size minus the number of estimated parameters ,.
df= n - p , where n= sample size , p = number of parameters.
According to the given problem , we have
Sample size : n=20
Number of parameters (x and y ): p= 2
Then, the df value for the standard error of estimate will be :
df= n-p =20-2=18
Thus , the df value for the standard error of estimate is 18 .
Hence, the correct answer is B) 18 .
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