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hodyreva [135]
2 years ago
3

A committee of four is formed from five eligible members. Let the eligible members be represented with A, B, C, D, and E. The po

ssible outcomes include S = {ABCD, BCDE, ACDE, ABCE, ABDE}. Which statements about the situation are true? Check all that apply.
There are 120 different ways to choose the committee.
If person A must be on the committee, there is only one way to form the committee.
If persons A and C must be on the committee, there are three ways to form the committee.
There are five ways to form the committee if person E must be on it.
If the number of eligible members increases, the number of outcomes increases.
Mathematics
2 answers:
OlgaM077 [116]2 years ago
8 0

The answer is C and E. I just answered the question and got it. :3

AfilCa [17]2 years ago
4 0
A
The first statement is false. The total number of ways of choosing 4 members from 5 is listed in the body of the question. There are 5 ways without any restrictions.

B
is false. If A must be on the committee then there are 4 ways of making forming he committee. What happens is that B C D and E are in turn left off the committee. 

C
I<em>f A and C are both on the committee then  this statement is true</em>. ABCD ACDE and ACBE are the three ways.

D
If E must be on it, the answer is the same as the answer for Choice B. This statement is false.

E
The question is ambiguous. How many people do you get to choose from? <em>If you are only going to choose a committee of 4 then the answer is true</em>. I will assume that is what is meant, but only the person making up the question can clear up the ambiguity.

The third and possibly the last statement are true.
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