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galina1969 [7]
2 years ago
10

A die is continuously rolled until the total sum of all rolls exceeds 375. what is the probability that at least 90 rolls are ne

cessary?
Mathematics
1 answer:
Tju [1.3M]2 years ago
5 0
We will have to divide 375 divided by 90 and that should give you the answer
or you can multiple the two numbers together to your answer
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If f(x)=x2+10sinx, show that there is a number c such that f(c)=1000.
gayaneshka [121]
F(x) is continuous for all x.

Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.

At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.

Let's pick 40.
At x = 40, f(40) - 1000 = 1600 + 10sin(40) - 1000 ≥ 0

Since f(x) - 1000 is continuous, there lies a root between 30 and 40, and hence, 30 ≤ c ≤ 40
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2 years ago
Determine the domain of each piece. Domain of piece 1:[) Domain of piece 2: [) Domain of piece 3:[
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Answer:

Domain of piece 1:[) -4,-1

Domain of piece 2: [) -1,1

Domain of piece 3:[] 1,5

Step 2:

Rule for piece 1: y=-x

Rule for piece 2: y=1

Rule for piece 3: y=2-x

Step-by-step explanation:

Correct on Edgen

6 0
2 years ago
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Louisa has a goal of collecting 100 pounds of dog food for a local shelter. She records how many pounds of food she collects eac
Anit [1.1K]

Answer:

28 more pouds of dog food

Step-by-step explanation:

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Charla works at a clothing store. Her pay is calculated using the formula
Mariana [72]
Can you write the question well because i don't get it.
3 0
2 years ago
Drag the values to order them from least to greatest, with the least at the top. Item 2 moved to position 3. 79 − − √ + 63 − − √
Nonamiya [84]

\sqrt{63} \\ \\ \sqrt{79}  \\ \\ \sqrt{143} \\ \\ 4\pi

<h2>Explanation:</h2>

As I understand, in this exercise, we have the following numbers:

\text{Number 1}=\sqrt{79} \\ \\ \text{Number 2}=\sqrt{63} \\ \\ \text{Number 3}=\sqrt{143} \\ \\ \text{Number 4}=4\pi

By using calculator, let's convert those numbers into decimal form:

\text{Number 1} \approx 8.88\\ \\ \text{Number 2} \approx 7.93 \\ \\ \text{Number 3} \approx 11.96 \\ \\ \text{Number 4} \approx 12.56

So arranging from least to greatest we have:

\text{Number 2} \\ \\ \text{Number 1} \\ \\ \text{Number 3} \\ \\ \text{Number 2}

Put another way:

\sqrt{63} \\ \\ \sqrt{79}  \\ \\ \sqrt{143} \\ \\ 4\pi

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2 years ago
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