in 2000, Jonesville had a population of 15,000. in 2001, the population was 16250 and in 2002, the population was 17,500. if the
2 answers:
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Answer:
a) f(-1/2) = -2 is NOT TRUE.
b) f(0) =3/2 is TRUE.
c) f(1) = -1 is NOT TRUE.
d) f(2) = 1 is NOT TRUE.
e) f(4) = 7/2 is TRUE.
Step-by-step explanation:
Here, the given function is
Now, checking for each values for the given function:
a) Putting x = (-1/2):
and (5/4) ≠ -2
Hence, f(-1/2) = -2 is NOT TRUE.
b)Putting x = 0 :
Hence, f(0) =3/2 is TRUE.
c) Putting x = 1:
Hence, f(1) = -1 is NOT TRUE.
d)Putting x = 2:
and (5/2) ≠ 1
Hence, f(2) = 1 is NOT TRUE.
e)Putting x = 4:
Hence, f(4) = 7/2 is TRUE.
Answer:
The <em>t</em>-value used for the 95% confidence interval of paired data is 2.776.
Step-by-step explanation:
The confidence interval formula for mean difference for a paired data is as follows:
Here,
= sample mean of the difference,
= sample standard deviation of the difference,
<em>n </em>= sample size (both samples are of same size).
= critical value of <em>t</em>
(<em>n</em> - 1) = degrees of freedom
The information provided is:
<em>n</em> = 5
Confidence level = 95%
The critical value of <em>t</em> is:
*Use a <em>t</em>-table for the critical value of <em>t</em>.
Thus, the <em>t</em>-value used for the 95% confidence interval of paired data is 2.776.
