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Sphinxa [80]
2 years ago
14

Use the table to answer the question. House A $124,270 Annual appreciation 4% House B $114,270 Annual appreciation 5% In which o

f these years after it was purchased is the value of House A greater than the value of House B? Check all that apply. 7 8 9 10
Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
4 0
For the house A we have:
 f (x) = 124270 (1.04) ^ x
 Evaluating for 7, 8, 9 and 10 we have:
 f (7) = 124270 (1.04) ^ 7 = 163530.8422
 f (8) = 124270 (1.04) ^ 8 = 170072.0759
 f (9) = 124270 (1.04) ^ 9 = 176874.9589
 f (10) = 124270 (1.04) ^ 10 = 183949.9573

 For house B we have:
 
f (x) = 114270 (1.05) ^ x
 Evaluating for 7, 8, 9 and 10 we have:
 f (7) = 114270 (1.05) ^ 7 = 160789.3653
 f (8) = 114270 (1.05) ^ 8 = 168828.8336
 f (9) = 114270 (1.05) ^ 9 = 177270.2752
 f (10) = 114270 (1.05) ^ 10 = 186133.789

 We observe that for years 7 and 8 the value of house A is greater than the value of house B.

 Answer:
 
7 and 8
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Use Gauss's Law to find the charge contained in the solid hemisphere x2 + y2 + z2 ≤ a2, z ≥ 0, if the electric field is E(x, y,
Anit [1.1K]

Answer:<em><u> \frac{16}{3}πa^{3} . </u></em>

Given:

x^{2}+y^{2}+z^{2} \leq a^{2}, z \geq 0

Using Gauss's Law = ∫∫s E ·dS  

= ∫∫∫ div E dV,  

⇒ Divergence (Gauss') Theorem  

= ∫∫∫ (1+1+6) dV  

= 8×(volume of the hemisphere, radius "a")  

= 8× (\frac{1}{2})(4/3)πa^{3}  

<em><u>= \frac{16}{3}πa^{3} . </u></em>

6 0
2 years ago
2. The restaurant bill you and your friend received was not itemized. You ordered 2 drink refills and the egg breakfast, for a t
fiasKO [112]
( a )   The system of equations:
2 r + b = 8.40
3 r + b = 9.35
( b ) Graph is in the attachment.
( c )  Each item costs:
 b = $6.50,  r = $0.95
We can prove it:  2 * 0.95 + 6.50 = 8.40
3* 0.95 + 6.50 = 9.35
Download docx
7 0
2 years ago
Jackson buys a grape snow cone on a hot day. By the time he eats all the "snow" off the top, the paper cone is filled with 27\pi
anyanavicka [17]

Question:

Jackson buys a grape snow cone on a hot day. By the time he eats all the "snow" off the top, the paper cone is filled with 27\pi27π27, pi cm^3 3 start superscript, 3, end superscript of melted purple liquid. The radius of the cone is 333 cm. What is the height of the cone?

Answer:

The height of the cone is 9 \ cm

Explanation:

It is given that the radius of the cone is 3 \ cm

The volume of the cone is 27\pi

The height of the cone can be determine using the formula,  

$V=\frac{1}{3} \pi r^{2} h$

Substituting the values V=27 \pi and r=3, we get,

$27 \pi=\frac{1}{3} \pi(3)^{2} h$

Multiplying both sides by 3, we have,

$81 \pi= 9\pi h$

Dividing both sides by $9 \pi$, we have,

9=h

Thus, the height of the cone is 9 \ cm

4 0
2 years ago
the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard dev
Naya [18.7K]

Answer:

a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 16, \sigma = 2.1

a. Find the probability that he is late for his first lecture.

This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 16}{2.1}

Z = 1.905

Z = 1.905 has a pvalue of 0.9716

1 - 0.9716 = 0.0284

2.84% probability that he is late for his first lecture.

b. Find the number of days per year he is likely to be late for his first lecture.

Each day, 2.84% probability that he is late for his first lecture.

Out of 180

0.0284*180 = 5.112 days

4 0
2 years ago
If ∠BAC = 17° and ∠CED = 17° are the two triangles, ΔBAC and ΔCED similar? If so, by what criterion?
Alborosie

No, not possible to tell that the the two triangles, ΔBAC and ΔCED

are similar ⇒ answer D

Step-by-step explanation:

Let us revise the cases of similarity

1. AAA similarity : two triangles are similar if all three angles in the first

  triangle equal the corresponding angle in the second triangle  

2. AA similarity : If two angles of one triangle are equal to the

   corresponding angles of the other triangle, then the two triangles  

   are similar.

3. SSS similarity : If the corresponding sides of the two triangles are

   proportional, then the two triangles are similar.

4. SAS similarity : In two triangles, if two sets of corresponding sides  

   are proportional and the included angles are equal then the two  

   triangles are similar.

In the two triangles BAC and CED

∵ m∠BAC = 17°

∵ m∠CED = 17°

∴ m∠BAC = m∠CED

But we need another pair of angles to prove that the two triangles are

similar by AA similarity criterion

<em>OR </em>

The lengths of sides BA , CA and CE , DE to show that

\frac{BA}{CE}=\frac{CA}{DE} = constant ratio and prove that the

two triangles are similar by SAS similarity criterion

So it is not possible to prove that the two triangles are similar

No, not possible to tell that the the two triangles, ΔBAC and ΔCED

are similar

Learn more:

You can learn more about triangles in brainly.com/question/4354581

#LearnwithBrainly

5 0
2 years ago
Read 2 more answers
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