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STALIN [3.7K]
1 year ago
5

A small cube of iron and a large flat sheet of iron contain the same volume. Which one will completely rust first? Explain why.

Chemistry
1 answer:
allochka39001 [22]1 year ago
6 0
Flat as more oxygen and water can react over it think of it like this would a cube rust faster than a sheet
Guest
1 year ago
Sample Response: The flat sheet will completely rust before the iron cube. Since they both have the same volume, the flat sheet has more surface area than the small cube. This means more particles are exposed on the flat sheet that can react in a chemical reaction
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Determine the overall charge on particles with the subatomic makeups given.
Gwar [14]

Answer:

The correct solution will be "+3".

Explanation:

The given values are:

Number of protons

= 13

Number of neutrons

= 14

Number of electrons

= 10

As we know,

⇒  Charge = Number \ of \ protons - Number \ of \ electrons

On putting the estimated values, we get

⇒               =13 - 10

⇒               =+3

5 0
2 years ago
A flask contains 1/3 mole of h2 and 2/3 mol of he. Compare the force on the wall per impact of h2 relative to that for he.
densk [106]

The force on the wall is actually the pressure exerted by gas molecules

Higher the pressure more the force exerted on the walls of container

The pressure depends upon the number of molecules of a gas

In a mixture of gas the pressure depends upon the mole fraction of the gas

As given the mole fraction of He is more than that of H2 therefore He will exert more pressure on the wall

The ratio of impact will be

H2 / He = 2/3 / 1/3 = 2: 1

8 0
1 year ago
Read 2 more answers
Use average bond energies to calculate ΔHrxn for the following hydrogenation reaction: H2C=CH2(g)+H2(g)→H3C−CH3(g)
marissa [1.9K]

Answer:

The\Delta H_{rxn} of the given reaction is -129.6 kJ

Explanation:

The given chemical reaction is as follows.

H_{2}C=CH_{2}(g)+H_{2}(g)\rightarrow H_{3}C-CH_{3}(g)

Enthalpy of each reactant and products are as follows.

\Delta H_{C=C}\,=615.0\,kJ\,mol^{-1}

\Delta H _{H-H}\,=435.1\,kJ\,mol^{-1}

\Delta H _{C-C}\,=347.3\,kJ\,mol^{-1}

\Delta H _{C-H}\,=416.2\,kJ\,mol^{-1}

In the given chemical reaction involved two C-H bonds in the reactant side and one C-C bond in the product side therefore, the enthalpy of formation will be the negative.

\Delta H_{rxn}=-\Delta H_{C-C}-2\Delta H_{C-H}+\Delta H_{C=C}+\Delta H_{H-H}

=-347.4-2\times416.2+615.0+435.1

=-129.6 \,kJ

Therefore, The\Delta H_{rxn} of the given reaction is -129.6 kJ

4 0
1 year ago
Hector claims that a single sodium ion and a single oxygen ion do not bond together to form a stable binary ionic compound. Is h
levacccp [35]

Answer:

C

Explanation:

Looking at the periodic table, we can see that sodium is in group 1, so a sodium ion would be Na⁺, with a charge of +1. Oxygen is in group 16, so an oxygen ion would be O²⁻, with a charge of -2.

A compound formed only by a single sodium ion and a single oxygen ion would thus have a charge of -1, and in order to have a stable ionic compound its charge must be zero.

8 0
1 year ago
Read 2 more answers
Both the esophagus and the small intestine are involved in the digestion of food. The esophagus squeezes food into the stomach b
UkoKoshka [18]

Answer:

The answer is: A

Explanation:

The wave-like contractions are to be considered a physical change as they do not take part in the breaking-down of the food. The peptidase is a chemical change because it is used to chemically break down the food to retrieve nutrients and such.

3 0
1 year ago
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