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damaskus [11]
2 years ago
6

The slope of the line below is 0.5. Write the equation of the line in point-slope form, using the coordinates of the labeled poi

nt. Do not use parenthesis on the y side.
Mathematics
1 answer:
Arturiano [62]2 years ago
8 0
The complete question is
The slope of the line below is 0.5 Write the equation of the line in point-slope form, using the coordinates of the labeled point. <span>It's on a number line which is (3,-3) Do not use parenthesis on the y side.

we know that

</span>Point slope form is 
<span>y - y₁ = m(x - x₁) </span>

<span>Where m= slope and (x₁, y₁) is a point on the line 
</span><span>Plug in m = 0.5 and point (3, -3) 
</span><span>y-(-3)=0.5*(x-3)------> y+3=0.5*(x-3)

the answer is
</span> y+3=0.5*(x-3)<span>


</span>
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frutty [35]
You could rewrite this as double brackets, as you are multiplying together two sets of two terms. It would then look like:
(8i + 6j)(4i + 5j)
and you can expand by multiplying together all of the terms

8i × 4i = 32i²
8i × 5j = 40ij
6j × 4i = 24ij
6j × 5j = 30j²

To get your final answer, you then just need to add together all of the like terms, and get 32i² + 30j² + 64ij

I hope this helps!
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2 years ago
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Alexxx [7]
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You could also multiply the whole number by 3 and the fraction by 3, ending up with 9 3/2, but then have to convert the improper fraction into a mixed number
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2 years ago
A circle has diameter of 11cm
dlinn [17]

Since length of diagonal (  Diagonal= 9.9cm ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.

<u>Step-by-step explanation:</u>

Here we have , A circle has diameter of 11 cm  A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:

We know the concept that for any square to fit inside the circle without touching the edge of circle  , diagonal of square must be less than diameter of circle  . Let's find out length of diagonal by using Pythagoras Theorem :

Hypotenuse ^2 = Perpendicular^2+Base^2

For a square , Perpendicular = base = side

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⇒ Diagonal= \sqrt{2}(7)

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5 0
2 years ago
A sequence has a common ratio of Three-halves and f(5) = 81. Which explicit formula represents the sequence? f(x) = 24(Three-hal
Ede4ka [16]

Answer:

f(x)=16\, (\frac{3}{2} )^{x-1}

Step-by-step explanation:

Since we are given the common ratio (3/2), all we need to find to define the geometric sequence, is its multiplicative factor (a) that corresponds to the first term of the sequence - remember that all consecutive terms will be generated by multiplying this first value repeatedly by the common ratio (3/2) as shown below:  

f(1)=a\\f(2)=a\,*\,(\frac{3}{2} )\\f(3)=a\,*\,(\frac{3}{2} )^2\\f(4)=a\,*\,(\frac{3}{2} )^3\\f(5)=a\,*\,(\frac{3}{2} )^4

Since we are given the information that f(5)=81 we can use this to find the value of the first term:

f(5)=\,a\,*\,(\frac{3}{2} )^4\\81=\,a\,*(\frac{81}{16} )\\a\,*\,81=\,81\.*\,16\\a\,=\,16

Notice as well that the first term doesn't contain the common ratio, the second term contains the common ration (3/2) to the power one, the third one contains the common ratio to the power two, the fourth one contains it to the power three, and so forth. So the exponent at which the common ratio appears is always one unit less than the order (x) of the term in question. This concept helps us finalize the expression for the sequence's formula:

f(x)=16\,*\,(\frac{3}{2} )^{x-1}

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