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Anuta_ua [19.1K]
2 years ago
14

The railroad crossing lights turn red, so mckayla and her sister must stop and wait for the train to pass by. as they wait, mcka

yla's sister kylie grabs her phone and uses an app to measure the frequency of the approaching train's horn. the app reads 429 hz. assuming the train's original horn frequency is 400 hz and the speed of sound is 330 m/s, how fast is the train going in m/s and miles per hour
Physics
1 answer:
maksim [4K]2 years ago
4 0
We can solve the problem by using the Doppler effect formula, which gives us the shift in frequency of a sound when the source is moving:
f'= ( \frac{v}{v+v_s} ) f
where
f' is the apparent frequency
v is the velocity of the wave
v_s is the velocity of the source relative to the observer
f is the original frequency

In our problem, f=400 Hz is the original frequency of the train's horn, f'=429 Hz is the apparent frequency read by the app, and v=330 m/s is the velocity of the wave (the speed of sound). If we re-arrange the formula, we can calculate v, the speed of the train:
v_s = v ( \frac{f}{f'}-1 )=(330 m/s)( \frac{400 Hz}{429 Hz}-1 )=-22.3 m/s
where the negative sign means the train is moving toward the two children.

In miles per hour, the velocity of the train is:
v=-22.3  \frac{m}{s} \cdot  \frac{1/1609 mil/m}{1/3600 h/s}= -49.9 mph
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Answer:

293.7 degrees

Explanation:

A = - 8 sin (37) i + 8 cos (37) j

A + B = -12 j

B = a i+ b j , where and a and b are constants to be found

A + B = (a - 8 sin (37) ) i + ( 8cos(37) + b ) j

- 12 j = (a - 8 sin (37) ) i + ( 8cos(37) + b ) j

Comparing coefficients of i and j:

a = 8 sin (37) = 4.81452 m

b = -12 - 8cos(37) = -18.38908

Hence,

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cos ( Q ) = 4.81452 / 12

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2 years ago
Hoosier Manufacturing operates a production shop that is designed to have the lowest unit production cost at an output rate of 1
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Answer:

90.77%

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Explanation:

The capacity utilisation rate can be expressed mathematically as;

Capacity utilisation rate = capacity used/Best operating level × 100%

Given;

Total Number of production time = 205hours

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2 years ago
A composite wall separates combustion gases at 2400°C from a liquid coolant at 100°C, with gas and liquid-side convection coeffi
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Answer:

\text{heat loss} = 24864.05 \  W/m^2

Explanation:

If

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then: part(a):

\text{heat loss } =  \frac{T_1 - T_2} { \frac{1}{h_1} + \frac{t_1}{t_2} + R_c + \frac{t_2}{k_2} + \frac{1}{h_2}}

using known values:

\text {heat loss} = 2486.05 W/m^2

part(b): Using the rate equation :

\text {heat loss} = h_1 (T_1 - T_{s1})

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and T_{c1} = T_{s1} - \frac {t_1 (\text{heat loss})}{k_1} = 1664.560 \ K

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Answer:

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