Question

An object pulled to the right by two forces has an acceleration of 2.5 m/s2. The free-body diagram shows the forces acting on the object.
A free body diagram with 4 force vectors. The first vector is pointing downward labeled F Subscript g Baseline, the second pointing up labeled F Subscript N Baseline. The third pointing right labeled F Subscript 1 Baseline = 50 N the last is from the tip of the third using the tail to tip method labeled F Subscript 2 Baseline = 75 N pointing right.

What is the weight of the object?

50 N
98 N
313 N
490 N

Answer 1

Answer:

Weight = 490 N

Explanation:

The two forces labeled $F_g$ and $F_N$ are the force of gravity and the normal force that the surface acts upon the object. These are equal and in opposite directions cancelling each other.

The other two forces $F_1$ and $F_2$ are both pointing to the right, and therefore add up to give a net force of:

50 N + 75 N = 125 N pointing to the right.

Since the net acceleration of the object is given as 2.5 $\frac{m}{s^2}$, we can use it in Newton's equation for the net force on an object  $F_{net}=m*a$ to solve for the object's mass:

$F_{net}=m*a\\125\,N=m*2.5 \frac{m}{s^2} \\m=\frac{125}{2.5} kg\\m=50\,kg$

Notice that since all units are in the SI system, the mass comes directly in kilograms (unit of mass in the SI system)

Now, to find the weight of the object, we multiply its mass times the acceleration of gravity (9.8 $\frac{m}{s^2}$):

Weight = $50 \,kg * g =50\,kg*9.8\frac{m}{s^2} =490\,N$

Again, since all quantities are expressed in SI units, the weight (a force) will come out in units of "Newtons" (N)

Answer 2

Answer:

490 n

Explanation: