Two waves are traveling in the same direction along a stretched string. The waves are 45.0° out of phase. Each wave has an ampli
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The molar latent enthalpy of boiling of iron at 3330 K is ΔH = 342 10^3 J.
<u>Explanation:</u>
Molar enthalpy of fusion is the amount of energy needed to change one mole of a substance from the solid phase to the liquid phase at constant temperature and pressure.
d ln p = (ΔH / RT^2) dt
(1/p) dp = (ΔH / RT^2) dt
dp / dt = p (ΔH / RT^2) = 3.72 10^-3
(p) (ΔH) / (8.31) (3330)^2 = 3.72 10^-3
ΔH = 342 10^3 J.
To solve this problem it is necessary to apply the concepts related to Newton's second law and the kinematic equations of movement description.
Newton's second law is defined as
Where,
m = mass
a = acceleration
From this equation we can figure the acceleration out, then
From the cinematic equations of motion we know that
Where,
Final velocity
Initial velocity
a = acceleration
x = displacement
There is not Final velocity and the acceleration is equal to the gravity, then
From the equation of motion where acceleration is equal to the velocity in function of time we have
Therefore the time required is 0.0705s
We have energy E = hc/λ, where h is Planck's constant c is speed of light and λ is the wavelength.
So Energy ,
Energy of one mol =
Energy of one mol of photons generated from this device = 225 kJ