Answer:
A. Increase in temperature is 0.0176 degree Celsius. b. the remaining energy will be lost.
Explanation:
The mass of copper block = 7kg
Initial speed = 4.0 m/s
Specific heat of copper = 0.385 j/g degree Celcius.
a. The increase in temperature is calculated below:
85% of energy is converted into internal energy.
b. The remaining 15 per cent of kinetic energy will be lost and it will be changed into other forms.
Answer:5.17 m/s
Explanation:
Given
let u be the speed at cliff initial point
range over cliff is 1.45 m
and range of projectile is given by
u=3.77 m/s
Conserving Energy
Kinetic energy=Kinetic energy +Potential energy gained
Let v be the initial velocity
Answer:
Impulse = 90
Resulting Velocity = 89
Explanation:
Use F * change in time = m * change in velocity.
For the first part of the question, the left side of the equation is the impulse. Plug it in.
60 * (3.0 - 0) = 90.
For the second half. we use all parts of the equation. I'm gonna use vf for the final velocity.
60 * (3.0 - 0) = 10 * (vf - 80). Simplify.
90 = 10vf - 800. Simplify again.
890 = 10vf. Divide to simplify and get the answer.
The resulting velocity is 89.
Answer:
592.92 x 10³ Pa
Explanation:
Mole of ammonia required = 10 g / 17 =0 .588 moles
We shall have to find pressure of .588 moles of ammonia at 30 degree having volume of 2.5 x 10⁻³ m³. We can calculate it as follows .
From the relation
PV = nRT
P x 2.5 x 10⁻³ = .588 x 8.32 x ( 273 + 30 )
P = 592.92 x 10³ Pa
Lets write again formula for determening Ann's performance.
P = 70.443 + 4,885*t
where t is in hours. This is equation with P(t) which means that P only depends on variable t. If we express t=2.6 in formula we will find her expected performance.
P = 83.144
Now, since it says that she scored 16 points less than expected we need to find value of P-16
P - 16 = 67.144
After round we get that the answer is 67
