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stiks02 [169]
1 year ago
13

Ginger is filing her federal income tax return with the 1040EZ form, and she received two W-2 forms, with the federal income tax

withheld on one being $4530, and the federal income tax withheld on the other being $540. If Ginger received a Making Work Pay credit of $400, and if lines 9a and 9b in the Payments, Credits, and Tax section below are $0, what should she enter on line 10?
A. $4670
B. $4930
C. $5470
D. $5070

Mathematics
2 answers:
kiruha [24]1 year ago
5 0
The answer is C. 5470
Maurinko [17]1 year ago
4 0

Answer - C

Add 4530 + 540 + 400 = 5470

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Find the area of irregular figure ​
elixir [45]

Step-by-step explanation:

For square

A=bh

A=30(20)

A=60in²

For triangle

A=½bh

A=½(40)(30)

A=½(120)

A=60in²

Add

60+60=120in²

8 0
2 years ago
If JK LM , which statement is true ?
siniylev [52]
The answer to this question would be: B. JK and LM meet at a right angle.

The reversed T symbol in this question means "perpendicular". That means the JK and LM line have 90-degree angle difference. A straight angle is 180 degree and right angle mean 90 degrees.
A perpendicular line should be in the same plane and intersect each other.
6 0
2 years ago
The championship record in baseball in a certain year was 52 games won, and 14 lost. What percent of the games were won?
slamgirl [31]
Number of games won/Number of total games played x 100%

52/66 x 100% = 78.79%

Hope u understood! :)
5 0
1 year ago
Mateus’s bank issued an advertisement saying that 90\%90%90, percent of its customers are satisfied with the bank’s services. Si
densk [106]

Answer:

The probability of getting a sample with 80% satisfied customers or less is 0.0125.

Step-by-step explanation:

We are given that the results of 1000 simulations, each simulating a sample of 80 customers, assuming there are 90 percent satisfied customers.

Let \hat p = <u><em>sample proportion of satisfied customers</em></u>

The z-score probability distribution for the sample proportion is given by;

                                Z  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, p = population proportion of satisfied customers = 90%

            n = sample of customers = 80

Now, the probability of getting a sample with 80% satisfied customers or less is given by = P( \hat p \leq 80%)

  P( \hat p \leq 80%) = P( \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } \leq \frac{0.80-0.90}{\sqrt{\frac{0.80(1-0.80)}{80} } } ) = P(Z \leq -2.24) = 1 - P(Z < 2.24)

                                                                  = 1 - 0.9875 = <u>0.0125</u>

The above probability is calculated by looking at the value of x = 2.24 in the z table which has an area of 0.9875.

8 0
2 years ago
Kate deposits $800 in a bank
Rina8888 [55]

Answer:

C

Step-by-step explanation:

Use formula

I=P\cdot r\cdot t,

where

I = interest

P = rpincipal

r = rate (as decimal)

t = time (in years)

In your case,

P = $800

r = 0.04 (4%)

t = 5,

so

I=\$800\cdot 0.04\cdot 5\\ \\I=\$160

6 0
1 year ago
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