Answer:
The final result is <u>2-methoxybutane. </u>
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Explanation:
1-butene has a carbon-carbon double bound between C1 and C2.
When it will react with methanol, in the presence of an acid, the result will be an ether.
C4H8 + CH3OH → C5H12O
An acid-catalyzed ether synthesis from alkenes is limited by carbocation stability.
In the first step, the double bound will disappear. The C2 atom will be a C+ atom, this becaus it has only 3 bounds and not 4.
This C+ -atom will atract the O- atom to form an ether. The CH3 of methanol will bind on the C3 atom, this is the most stable position.
2-methoxybutane will be formed. It has a structural formula of C5H12O
1-methoxybutane will not be formed, because it's less stable.
1-butanol will be formed when water is added to 1-butene. The mechanism has the same principle but not the same product.
1-ethoxybutane and 2-ethoxybutane have a structural formula of C6H14O, this will not be the final result.
The final result is <u>2-methoxybutane. </u>
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