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2 years ago

Which statement best describes how an ionic bond forms?

Chemistry

2 answers:

const2013 [10]2 years ago

5 0

The answer is (A) The transfer of electrons forms strong bonds between ions.

maxonik [38]2 years ago

4 0

<span>The question says,'which statement best describes how an ionic bond forms. The correct option is A. Ionic bonds are formed as a result of complete transfer of electrovalence electrons from one atom to another. The atom that donate the electron become a positively charged ion while the atom that received the atom become a negatively charged ion.</span>

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On a clear day at sea level, with a temperature of 25 °C, the partial pressure of N2 in air is 0.78 atm and the concentration of

joja [24]

Answer : The partial pressure of nitrogen gas is, 2.94 atm

Explanation:

According top the Henry's Law, the concentration of a gas in a liquid is directly proportional to the partial pressure of the gas.

$C\propto P$

$C=K_H\times P$

$K_H$ is Henry's constant.

or,

$\frac{C_1}{C_2}=\frac{P_1}{P_2}$

where,

$C_1$ = initial concentration of gas = $5.3\times 10^{-4}M$

$C_2$ = final concentration of gas = $2.0\times 10^{-3}M$

$P_1$ = initial partial pressure of gas = 0.78 atm

$P_2$ = final partial pressure of gas = ?

Now put all the given values in the above formula, we get the final partial pressure of the gas.

$\frac{5.3\times 10^{-4}M}{2.0\times 10^{-3}M}=\frac{0.78atm}{P_2}$

$P_2=2.94atm$

Therefore, the partial pressure of nitrogen gas is, 2.94 atm

5 0

2 years ago

This stadium can hold 100,000, or 1 x 105, people. The number of atoms in a grain of iron is about 1 x 1018. Would you need 1 x

nata0808 [166]

<h3>Answer:</h3>

1 x 10^13 stadiums

<h3>Explanation:</h3>

We are given that;

1 stadium holds = 1 × 10^5 people

Number of iron atoms is 1 × 10^18 atoms

Assuming the stadium would carry an equivalent number of atoms as people.

Then, 1 stadium will carry 1 × 10^5 atoms

Therefore,

To calculate the number of stadiums that can hold 1 × 10^18 atoms we divide the total number of atoms by the number of atoms per stadium.

Number of stadiums = Total number of atoms ÷ Number of atoms per stadium

= 1 × 10^18 atoms ÷ 1 × 10^5 atoms/stadium

= 1 × 10^13 Stadiums

Thus, 1 × 10^18 atoms would occupy 1 × 10^13 stadiums

7 0

2 years ago

If a collision between molecules is very gentle the molecules are

Nadya [2.5K]

If collision between molecules is very gentle the molecules are more likely to bound without reaction

collision is process in which molecules come together or collide with one another.Molecules must collide with sufficient energy so that chemical bond can break. In addition for collision to occur there must have favorable orientation.

6 0

2 years ago

What mass of fes is formed if 9.42 g of fe reacts with 68.0 g of s8? 8fe(s) + s8(s) â†’ 8fes(s)?

allochka39001 [22]

From the equation, we see that the molar ratio of Fe : S required is:

8 : 1

The moles of Fe present are: 9.42/56 = 0.168
Moles of S = 68/(32 * 8) = 0.265

The molar ratio is:

1 : 1.6

Therefore, iron is the limiting reactant as it is present in a ratio lower than that required. The ratio of

Fe : FeS is
1 : 1

So 0.168 moles of FeS will form. The mass of FeS will be:

Mass = 0.168 * (56 + 32)
Mass = 14.78 grams

14.78 grams of FeS will be formed.

4 0

2 years ago

In a certain compound of iron and oxygen, FexOy, it is found that a sample of this compound weighing 6.285 g contains 4.396 g of

saveliy_v [14]

Answer:

Formula of oxide is $Fe_{2}O_{3}$

Explanation:

The given compound consists of Fe and O.

So, mass of oxygen in sample = (mass of sample) - (mass of Fe in sample)

= (6.285 g ) - (4.396 g)

= 1.889 g

Molar mass of O = 16 g/mol and molar mass of Fe = 55.845 g/mol

So, ratio of number of moles of Fe and O (Fe : O)

= $\frac{4.396}{55.845}:\frac{1.889}{16}$

= 0.0787 : 0.118

= $1:\frac{0.118}{0.0787}$

= 1 : 1.5

= 2 : 3

So, formula of oxide is $Fe_{2}O_{3}$

5 0

2 years ago