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Sedaia [141]
2 years ago
7

The amount of a sample remaining after t days is given by the equation mc001-1.jpg, where A is the initial amount of the sample

and h is the half-life, in days, of the substance. A scientist has a 10-mg sample of a radioactive isotope. The isotope has a half-life of 8 days. After 16 days, how much of the radioactive isotope remains? 2.0 mg 2.5 mg 5.7 mg 7.1 mg
Mathematics
2 answers:
vichka [17]2 years ago
8 0

Answer:

b. 2.5 mg

just took the test on edge

kherson [118]2 years ago
5 0

P(t)= A(1/2)^(t/h)

P(t)=10(1/2)^(16/8)

<em>(1/2)^(16/8) =.25</em>

P(t)=10(.25)

P(t)=2.5

Therefore the answer is B. 2.5mg.

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Answer:

We conclude that the sample is from a population of songs with a mean greater than 210 seconds.

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Let \mu = <u><em>population mean length of the songs</em></u>

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Alternate Hypothesis, H_A : \mu > 210 seconds      {means that the sample is from a population of songs with a mean greater than 210 seconds}

The test statistics that will be used here is <u>One-sample z-test statistics </u>because we know about population standard deviation;

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where, \bar X = sample mean length of songs = 252.5 seconds

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So, <u><em>the test statistics</em></u> =  \frac{252.5-210}{\frac{54.5}{\sqrt{40} } }

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The value of z-test statistics is 4.932.

Now, at 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 4.932 > 1.645, so <u><em>we have sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the sample is from a population of songs with a mean greater than 210 seconds.

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