In the diagram of circle A, what is the measure of ∠XYZ?

The perimeter of a triangle is 76cm side of the triangle is twice as long as side b .side c is 1 cm longer than a side a .find t

stepladder [879]

P= a+b+c = 76
side a = 2b = 30
side b = b = 15
side c = 2b + 1 = 31

7 0

2 years ago

Ben Spender writes a $60 check which is retumed by his bank with additional charges. The company he wrote the

pshichka [43]

Answer:

$80

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The Rockville Employment Agency just placed Howard Jacobson in a job as a junior pharmacist. The job pays $51.2k. The agency fee

yan [13]

His annual salary as a pharmacist is $51,200

There are a total of 52 weeks in an year.

(a) Weekly salary = annual salary/ number of weeks = 51,200/52 = $984.62 (rounded to the nearest cent)

Howard's weekly salary to the nearest cent = $984.62

(b) His salary in first three weeks = 984.62*3 = $2,953.85

Howard's earnings during the first three weeks to the nearest cent = $2,953.85

(c) He has to pay the agency 40% of his three week salary which is = 0.4*2953.85 =1,181.54

Howard must pay to the employment agency to the nearest dollar = $1,182

6 0

2 years ago

Exclude leap years from the following calculations. (a) Compute the probability that a randomly selected person does not have a

Scrat [10]

Answer:

a) 99.73% probability that a randomly selected person does not have a birthday on March 14.

b) 96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

c) 98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

d) 92.33% probability that a randomly selected person was not born in February.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

A non-leap year has 365 days.

(a) Compute the probability that a randomly selected person does not have a birthday on March 14.

There are 365-1 = 364 days that are not March 14. So

364/365 = 0.9973

99.73% probability that a randomly selected person does not have a birthday on March 14.

(b) Compute the probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

There are 12 months, so there are 12 2nds of a month.

So

(365-12)/365 = 0.9671

96.71% probability that a randomly selected person does not have a birthday on the 2 nd day of a month.

(c) Compute the probability that a randomly selected person does not have a birthday on the 31 st day of a month.

The following months have 31 days: January, March, May, July, August, October, December.

So there are 7 31st days of a month during a year.

Then

(365-7)/365 = 0.9808

98.08% probability that a randomly selected person does not have a birthday on the 31 st day of a month.

(d) Compute the probability that a randomly selected person was not born in February.

During a non-leap year, February has 28 days. So

(365-28)/365 = 0.9233

92.33% probability that a randomly selected person was not born in February.

6 0

2 years ago

In 1990, the mean duration of long-distance telephone calls originating in one town was 7.2 minutes. A long-distance telephone c

scoundrel [369]

Answer:

We know that In 1990, the mean duration of long-distance telephone calls originating in one town was 7.2 minutes. And we want to test if the mean duration of long-distance phone calls has changed from the 1990 mean of 7.2 minutes (alternative hypothesis) and the complement rule would represent the null hypothesis.

The correct system of hypothesis are:

Null hypothesis: $\mu =7.2$

Alternative hypothesis: $\mu \neq 7.2$

So then the best option for this case would be:

H0: μ = 7.2 minutes Ha: μ ≠ 7.2 minutes

Step-by-step explanation:

We know that In 1990, the mean duration of long-distance telephone calls originating in one town was 7.2 minutes. And we want to test if the mean duration of long-distance phone calls has changed from the 1990 mean of 7.2 minutes (alternative hypothesis) and the complement rule would represent the null hypothesis.

The correct system of hypothesis are:

Null hypothesis: $\mu =7.2$

Alternative hypothesis: $\mu \neq 7.2$

So then the best option for this case would be:

H0: μ = 7.2 minutes Ha: μ ≠ 7.2 minutes

And in order to test the hypothesis we can use a one sample t test or z test depending if we know the population deviation or not

4 0

2 years ago