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2 years ago

Which of the following proportions can be used to prove AE || DK in the proof below? Select all that apply.

Mathematics

2 answers:

Ira Lisetskai [31]2 years ago

8 0

Triangle AEF and triangle DFK are similar to each other, this implies that the ratio of the corresponding sides are equal. Hence:
Using the proportions and ratio we have
the correct statement is:
b

Galina-37 [17]2 years ago

5 0

Answer: DA:FA=KE:EF, DF:DA=KF:KE and FA:DA=EF:KE are correct.

Explanation: Since, $\triangle EFA$ and $\triangle KFD$ are similar triangles.

Because, $\angle FAE= \angle FDK$ and $\angle FEA= \angle FKD$ (because EA and KD are parallels. And, $\angle F$ is common angle for these triangles.

Therefore, according to the property of similar triangles.

FE:EK= FA:AD, FE:FK=FA:FD and DF:DA=KF:KE .

Thus, first, second and third options are correct.

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Find the mean, median and mode of the weights of the people shown. 105kg 53kg 76kg 91kg 120kg 61kg 55kg 98kg 61kg

Yuliya22 [10]

First, you need to put them in order
53kg, 55kg, 61kg, 61kg, 76kg, 91kg, 98kg, 105kg, 120kg

For mean, you add them all up and divide by the amount of numbers (9)
720/9 = 80

For median, you find the middle number (76kg)

For mode, you find the number that appears the most (61kg)

Mean: 80
Median: 76
Mode: 61

5 0

2 years ago

Read 2 more answers

Show all your work. Indicate clearly the methods you use, because you will be scored on the correctness of your methods as well

laiz [17]

Answer:

The value is $P(A) = 0.133617$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 7.5$

The standard deviation is $\sigma = 0.2$

The safest water level is between 7.2 and 7.8

Generally the probability that the selected pool has a pH level that is not considered safe is mathematically represented as

$P(A) = 1 - P(7.2 \le X \le 7.8 )$

Here

$P(7.2 < X < 7.8 ) = P(\frac{ 7.2 - \mu }{\sigma } < \frac{X - \mu }{ \sigma }$

Generally $\frac{X - \mu }{ \sigma } = Z (The \ standardized \ value \ of X )$

$P(7.2 < X < 7.8 ) = P(\frac{ 7.2 - 7.5 }{0.2 } < Z$

$P(7.2 < X < 7.8 ) = P(-1.5 < Z$

=> $P(7.2 < X < 7.8 ) = P(Z < 1.5) - P( Z < - 1.5)$

From the z-table the probability of (Z < -1.5) and ( Z <1.5) are

$P(Z < 1.5) = 0.93319$

and

$P(Z < -1.5) = 0.066807$

$P(7.2 < X < 7.8 ) =0.93319 - 0.066807$

$P(7.2 < X < 7.8 ) =0.0866383$

$P(A) = 1 - 0.0866383$

=> $P(A) = 0.133617$

5 0

2 years ago

The following histogram summarizes the number of points Nate has scored each game this season.

Tatiana [17]

Answer:D

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What did you do to find the GCF given the remaining factors?

scoray [572]

Answer:

To find GCD or HCF, just write the common factor.

Step-by-step explanation:

To find the GCF of greater numbers, you can factor each number to find their prime factors, identify the prime factors they have in common, and then multiply those together.

8 0

2 years ago

The probability of a train arriving on time and leaving on time is 0.8. The probability that the train arrives on time and leave

kkurt [141]

Answer:

0.9524

Step-by-step explanation:

Note enough information is given in this problem. I will do a similar problem like this. The problem is:

The Probability of a train arriving on time and leaving on time is 0.8.The probability of the same train arriving on time is 0.84. The probability of the same train leaving on time is 0.86.Given the train arrived on time, what is the probability it will leave on time?

Solution:

This is conditional probability.

Given:

Probability train arrive on time and leave on time = 0.8
Probability train arrive on time = 0.84
Probability train leave on time = 0.86

Now, according to conditional probability formula, we can write:

$P(Leave \ on \ time | arrive \ on \ time)$ = P(arrive ∩ leave) / P(arrive)

Arrive ∩ leave means probability of arriving AND leaving on time, that is given as "0.8"

and

P(arrive) means probability arriving on time given as 0.84, so:

0.8/0.84 = 0.9524

This is the answer.

5 0

2 years ago