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andrey2020 [161]
2 years ago
7

Which of the following proportions can be used to prove AE || DK in the proof below? Select all that apply.

Mathematics
2 answers:
Ira Lisetskai [31]2 years ago
8 0
Triangle AEF and triangle DFK are similar to each other, this implies that the ratio of the corresponding sides are equal. Hence:
Using the proportions and ratio we have
 the correct statement is:
b
Galina-37 [17]2 years ago
5 0

Answer: DA:FA=KE:EF, DF:DA=KF:KE and FA:DA=EF:KE are correct.

Explanation: Since, \triangle EFA and \triangle KFD are similar triangles.

Because, \angle FAE= \angle FDK and \angle FEA= \angle FKD (because EA and KD are parallels. And, \angle F is common angle for these triangles.

Therefore, according to the property of similar triangles.

FE:EK= FA:AD, FE:FK=FA:FD and DF:DA=KF:KE .

Thus, first, second and third options are correct.

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Find the mean, median and mode of the weights of the people shown. 105kg 53kg 76kg 91kg 120kg 61kg 55kg 98kg 61kg
Yuliya22 [10]
First, you need to put them in order
53kg, 55kg, 61kg, 61kg, 76kg, 91kg, 98kg, 105kg, 120kg

For mean, you add them all up and divide by the amount of numbers (9)
720/9 = 80

For median, you find the middle number (76kg)

For mode, you find the number that appears the most (61kg)

Mean: 80
Median: 76
Mode: 61
5 0
2 years ago
Read 2 more answers
Show all your work. Indicate clearly the methods you use, because you will be scored on the correctness of your methods as well
laiz [17]

Answer:

The  value is  P(A) =  0.133617

Step-by-step explanation:

From the question we are told that

  The  mean is  \mu =  7.5

  The standard deviation is  \sigma  =  0.2

  The safest water level is  between  7.2 and  7.8

Generally the probability that the selected pool has a pH level that is not considered safe is mathematically represented as

       P(A) =  1 - P(7.2 \le X  \le 7.8 )

Here  

      P(7.2 < X  < 7.8 ) = P(\frac{ 7.2 - \mu }{\sigma } <  \frac{X - \mu }{ \sigma }

Generally \frac{X - \mu }{ \sigma } =  Z (The  \ standardized \  value  \  of  X )

So

 P(7.2 < X  < 7.8 ) = P(\frac{ 7.2 - 7.5 }{0.2 } < Z    

 P(7.2 < X  < 7.8 ) = P(-1.5 < Z  

=>  P(7.2 < X  < 7.8 ) = P(Z <  1.5) - P(  Z < - 1.5)

From the z-table the probability of  (Z <  -1.5) and   (  Z <1.5)  are

    P(Z <  1.5) =  0.93319

and  

    P(Z <  -1.5) =  0.066807

So

      P(7.2 < X  < 7.8 ) =0.93319 - 0.066807

       P(7.2 < X  < 7.8 ) =0.0866383

So

   P(A) =  1 - 0.0866383

=>  P(A) =  0.133617

5 0
2 years ago
The following histogram summarizes the number of points Nate has scored each game this season.
Tatiana [17]

Answer:D

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What did you do to find the GCF given the remaining factors?​
scoray [572]

Answer:

To find GCD or HCF, just write the common factor.

Step-by-step explanation:

To find the GCF of greater numbers, you can factor each number to find their prime factors, identify the prime factors they have in common, and then multiply those together.

8 0
2 years ago
The probability of a train arriving on time and leaving on time is 0.8. The probability that the train arrives on time and leave
kkurt [141]

Answer:

<u>0.9524</u>

Step-by-step explanation:

<em>Note enough information is given in this problem. I will do a similar problem like this. The problem is:</em>

<em>The Probability of a train arriving on time and leaving on time is 0.8.The probability of the same train arriving on time is 0.84. The probability of the same train leaving on time is 0.86.Given the train arrived on time, what is the probability it will leave on time?</em>

<em />

<u>Solution:</u>

This is conditional probability.

Given:

  • Probability train arrive on time and leave on time = 0.8
  • Probability train arrive on time = 0.84
  • Probability train leave on time = 0.86

Now, according to conditional probability formula, we can write:

P(Leave \ on \  time | arrive \  on \ time) = P(arrive ∩ leave) / P(arrive)

Arrive ∩ leave means probability of arriving AND leaving on time, that is given as "0.8"

and

P(arrive) means probability arriving on time given as 0.84, so:

0.8/0.84 = <u>0.9524</u>

<u></u>

<u>This is the answer.</u>

5 0
2 years ago
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