Answer:
3 customers brought all the three papers.
Step-by-step explanation:
Let, D, O and N represents the three newspapers.
D = The daily times
O = The observer
N = The new Nigeria.
According to the given information,
We know that,
Using this formula, we get
Therefore, 3 customers brought all the three papers.
2(18+11)
i think this is the expression you are looking for
(a) The probability that there is no open route from A to B is (0.2)^3 = 0.008.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:
(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:
β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:
Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:
Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.
This is late, but for anyone searching the answer up in the future, the answer on Edg.enuity is the last one - where the graph starts out as a horizontal line, then decreases and touches the x-axis, then increases again.
Good luck on your assignment !!
1.6 I think I’m sorry if it’s incorrect
