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2 years ago

Help please!!! What is P(0.6 ≤ z ≤ 2.12)? 16% 26% 73% 98%

Mathematics

2 answers:

Stels [109]2 years ago

8 0

Answer:

The correct option is 2.

Step-by-step explanation:

We have to find the value of P(0.6 ≤ z ≤ 2.12).

$P(0.6\leq z\leq 2.12)=P(z\leq 2.12)-P(z< 0.6)$

From the Cumulative Standardized Normal Distribution table,

$P(z\leq 2.12)=0.9830$

$P(z$

$P(0.6\leq z\leq 2.12)=0.9830-0.7257$

$P(0.6\leq z\leq 2.12)=0.2573$

$P(0.6\leq z\leq 2.12)\approx 0.26=26\%$

Therefore the correct option is 2.

Lelu [443]2 years ago

5 0

26% is the answer to your question

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7 0

2 years ago

15 Points!

goblinko [34]

Answer:

coordinate of point A is (a,b)

coordinate of point C is (2c,d)

slope of AD and BC = $\frac{b}{a-c}$

Step-by-step explanation:

According to midpoint formula

If we have points P $(x_{1} ,y_{1} )$ and Q $(x_{2} ,y_{2} )$

then the coordinate (x,y) of mid point of line PQ is given by

$x=\frac{x_{1} +x_{2} }{2}$ and $y=\frac{y_{1} +y_{2} }{2}$

now from the given diagram A is the mid point of line joining R(0,0) and S(2a,2b)

Using midpoint formula, coordinates of point A is given by

$x=\frac{0+2a}{2}= a$ and $y=\frac{0+2b}{2} =b$

so we have

coordinate of point A is (a,b)

Also C is the midpoint of line joining T (2c,2d) and V(2c,0)

coordinate of point C is given by

$x= \frac{2c+2c}{2} =2c$ and $y=\frac{2d+0}{2} =d$

so we have

coordinate of point C is (2c,d)

it is given that coordinate of point B is (a+c, b+d) and coordinate of D is (c,0)

If we have points P $(x_{1} ,y_{1} )$ and Q $(x_{2} ,y_{2} )$

then the slope of PQ = $\frac{y_{2} -y_{1} }{x_{2}-x_{1} }$

hence slope of AD= $\frac{0-b }{c-a}$

= $\frac{-b}{c-a}$

= $\frac{-b}{-(a-c)}$

= $\frac{b}{a-c}$

and slope of BC = $\frac{d-(b+d)}{2c-(a+c)}$

= $\frac{d-b-d}{2c-a-c}$

= $\frac{-b}{c-a}$

= $\frac{b}{a-c}$

so we have

slope of AD and BC = $\frac{b}{a-c}$

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