All categories

1 year ago

Help please!!! What is P(0.6 ≤ z ≤ 2.12)? 16% 26% 73% 98%

Mathematics

2 answers:

Stels [109]1 year ago

8 0

Answer:

The correct option is 2.

Step-by-step explanation:

We have to find the value of P(0.6 ≤ z ≤ 2.12).

$P(0.6\leq z\leq 2.12)=P(z\leq 2.12)-P(z< 0.6)$

From the Cumulative Standardized Normal Distribution table,

$P(z\leq 2.12)=0.9830$

$P(z$

$P(0.6\leq z\leq 2.12)=0.9830-0.7257$

$P(0.6\leq z\leq 2.12)=0.2573$

$P(0.6\leq z\leq 2.12)\approx 0.26=26\%$

Therefore the correct option is 2.

Lelu [443]1 year ago

5 0

26% is the answer to your question

You might be interested in

The article "Expectation Analysis of the Probability of Failure for Water Supply Pipes"† proposed using the Poisson distribution

oksian1 [2.3K]

Answer:

a. P(X ≤ 5) = 0.999

b. P(X > λ+λ) = P(X > 2) = 0.080

Step-by-step explanation:

We model this randome variable with a Poisson distribution, with parameter λ=1.

We have to calculate, using this distribution, P(X ≤ 5).

The probability of k pipeline failures can be calculated with the following equation:

$P(k)=\lambda^{k} \cdot e^{-\lambda}/k!=1^{k} \cdot e^{-1}/k!=e^{-1}/k!$

Then, we can calculate P(X ≤ 5) as:

$P(X\leq5)=P(0)+P(1)+P(2)+P(4)+P(5)\\\\\\P(0)=1^{0} \cdot e^{-1}/0!=1*0.3679/1=0.368\\\\P(1)=1^{1} \cdot e^{-1}/1!=1*0.3679/1=0.368\\\\P(2)=1^{2} \cdot e^{-1}/2!=1*0.3679/2=0.184\\\\P(3)=1^{3} \cdot e^{-1}/3!=1*0.3679/6=0.061\\\\P(4)=1^{4} \cdot e^{-1}/4!=1*0.3679/24=0.015\\\\P(5)=1^{5} \cdot e^{-1}/5!=1*0.3679/120=0.003\\\\\\P(X\leq5)=0.368+0.368+0.184+0.061+0.015+0.003=0.999$

The standard deviation of the Poisson deistribution is equal to its parameter λ=1, so the probability that X exceeds its mean value by more than one standard deviation (X>1+1=2) can be calculated as:

$P(X>2)=1-(P(0)+P(1)+P(2))\\\\\\P(0)=1^{0} \cdot e^{-1}/0!=1*0.3679/1=0.368\\\\P(1)=1^{1} \cdot e^{-1}/1!=1*0.3679/1=0.368\\\\P(2)=1^{2} \cdot e^{-1}/2!=1*0.3679/2=0.184\\\\\\P(X>2)=1-(0.368+0.368+0.184)=1-0.920=0.080$

4 0

1 year ago

riddle me this I'm thinking of a number it is odd is between 1 and 100 is higher than 20 it is smaller than the answer to 6 time

Bogdan [553]

I think it might be 27

6 0

2 years ago

Read 2 more answers

In △ABC,c=71, m∠B=123°, and a=65. Find b. A. 101.5 B. 117.8 C. 123.0 D. 119.6

tia_tia [17]

Answer:

Option D

Step-by-step explanation:

The questions which involve calculating the angles and the sides of a triangle either require the sine rule or the cosine rule. In this question, the two sides that are given are adjacent to each other the given angle is the included angle. This means that the angle B is formed by the intersection of the lines a and c. Therefore, cosine rule will be used to calculate the length of b. The cosine rule is:

b^2 = a^2 + c^2 - 2*a*c*cos(B).

The question specifies that c=71, B=123°, and a=65. Plugging in the values:

b^2 = 65^2 + 71^2 - 2(65)(71)*cos(123°).

Simplifying gives:

b^2 = 14293.0182932.

Taking square root on the both sides gives b = 119.6 (rounded to the one decimal place).

This means that the Option D is the correct choice!!!

8 0

2 years ago

An object is moving at a speed of 230 feet per week. Express this speed in inches per minute. Round your answer to the nearest h

Kruka [31]

Answer:

0.02 inches per minute

Step-by-step explanation:

1 Week = 10080 minutes

Formaul: multiply the time value by 10080 to find the minutes in a week or do it the long way 60x24x7 = 10080

230/10080 = 0.02281746031 or 0.02 rounded to nearest hundert.

5 0

2 years ago

Rajeev has \$175$175dollar sign, 175 that he earned from his summer job. He puts the money in an account that yields 4\%4%4, per

Reptile [31]

It will take 4 yrs for Rajeev to reach 200$

8 0

2 years ago