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zepelin [54]
2 years ago
5

If the mean, median and mode of a distribution are 5, 6, 7 respectively, then the distribution is:

Mathematics
1 answer:
QveST [7]2 years ago
3 0
<span>the distribution is 43

</span>
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What is 528−−√+63−−√528+63 in simplest radical form?
Montano1993 [528]

Answer: 13\sqrt{7}

Step-by-step explanation:

In the simple radical form there are no square root is remain to find.

Since, the given expression,

5\sqrt{28} + \sqrt{63}

5\sqrt{4\times 7} + \sqrt{9\times 7}

5\sqrt{4} \times \sqrt{7} + \sqrt{9}\times \sqrt{7}

5\times 2 \times \sqrt{7} + 3\times \sqrt{7}

10 \sqrt{7} + 3\sqrt{7}

(10 + 3)\sqrt{7}

13\sqrt{7}

Since, we do not need to find further square root of 7.

Thus, the required radical form of 5\sqrt{28} + \sqrt{63} is 13\sqrt{7}.

6 0
2 years ago
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Which value of x would make FG II BC?<br><br> 1<br> 3<br> 6<br> 9
Veseljchak [2.6K]
 x - 1        x + 1
------ = --------------
x + 3       x + 6

if x = 9
8/ 12 = 10/15

12 (10) = 8(15)
120 = 120

so 
answer is 9 (last choice)

7 0
2 years ago
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to estimate the number of bison in the area, researchers put marks on 160 bison later on a flight over the area the researchers
Dvinal [7]
Its either -126 or 160
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2 years ago
an angle measures 62 degrees less than the measure of its complementary angle. what is the measure of each angle
Yuki888 [10]

Answer:

Step-by-step explanation:

What is a complementary angle?

3 0
2 years ago
A university surveyed recent graduates of the English department for their starting salaries. Four hundred graduates returned th
NeX [460]

Answer:

Step-by-step explanation:

We want to determine a 95% confidence interval for the mean salary of all graduates from the English department.

Number of sample, n = 400

Mean, u = $25,000

Standard deviation, s = $2,500

For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean ± z × standard deviation/√n

It becomes

25000 ± 1.96 × 2500/√400

= 25000 ± 1.96 × 125

= 25000 ± 245

The lower end of the confidence interval is 25000 - 245 =24755

The upper end of the confidence interval is 25000 + 245 = 25245

Therefore, with 95% confidence interval, the mean salary of all graduates from the English department is between $24755 and $25245

3 0
2 years ago
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