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Afina-wow [57]
2 years ago
6

Suppose that 37.4% of all college football teams had winning records in 1998, and another 24.8% broke even. What is the probabil

ity that a randomly chosen college football team had a losing record in 1998?
Mathematics
2 answers:
PilotLPTM [1.2K]2 years ago
6 0

Answer:

0.378

Step-by-step explanation:

Given that 37.4% of all college football teams had winning records in 1998, and another 24.8% broke even

i.e.if total college students are 100, 37.4 will win and 24.8 will break even

(Here we should not take literally decimals because these are examples.)

Losers = 100-37.4-24.8 = 100-62.2 = 37.8

Hence probability that a randomly chosen college football team had a losing record in 1998

=37.8%\\=0.378

Eddi Din [679]2 years ago
4 0
Let’s say there are 1000 football teams.

Having winning records in 1998-> 374
Broke the winning records-> 248


Losing record-> 1000-374-248=378

Total=1000

-> 37.8% (378/1000 *100)
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