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inessss [21]
2 years ago
3

A first alloy contains $x$ pounds of 50% silver. it is mixed with a second alloy containing 15% silver to make 35 pounds of an a

lloy containing 38% silver. of the answers listed below, the one closest to the correct value of $x$ is
Mathematics
1 answer:
Karolina [17]2 years ago
8 0
Let first alloy contains x pounds of silver, which is 50% of full weight, then the weight of first alloy is 2x. 

The second alloy has weight 35-2x pounds and contains 15% silver, then weight of silver in this alloy is (35-2x)*0.15 pounds.
35 pounds of mixed alloy contains 38% silver, that is 35*0.38=13.3 pounds.

If you add the weights of silver from two alloys you obtain the weight 13.3 pounds (the weight of silver in mixed alloy).x+(35-2x)*0.15=13.3x+5.25-0.3x=13.3
0.7x=13.3-5.25=8.05

x=8.05÷0.7=11.5 pounds (<span>silver content in the first alloy) and 2x=23 pounds is the weight of first alloy.</span>
<span /><span>
</span><span>35-23=12 pounds is the weight of second alloy and 12*0.15=1.8 pounds (silver content in the second alloy).
</span>



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Question 1(Multiple Choice Worth 2 points)
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These are 3 questions and 3 answers.

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\lim_{x \to \ 2^+} f(x)

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perimeter of rectangle : p = 2(L + W)
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so if the perimeters are te same, lets set them equal to each other and solve for x

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