Answer:
Step-by-step explanation:
Given a circle centre J
Let the radius of the circle =r
LK is tangent to circle J at point K
From the diagram attached
Theorem: The angle between a tangent and a radius is 90 degrees.
By the theorem above, Triangle JLK forms a right triangle with LJ as the hypotenuse.
Using Pythagoras Theorem:
The length of the radius, 
Answer:
yes 30 is the answer
Step-by-step explanation:
Answer:
The answer is C. Lila made an error in Step 3 when she did not use the x- and y-coordinates from the same ordered pair.
Hope this helps!
Stay safe at home :)
(those of you doing edge hang in there!)
∆ABC has vertices at A(12, 8), B(4, 8), and C(4, 14). ∆XYZ has vertices at X(6, 6), Y(4, 12), and Z(10, 14). ∆MNO has vertices a
koban [17]
To get the length of each side,
use the distance formula with equation:
Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
Solving
<span>AB = 8 units BC = 6 units AC = 10 units
</span><span>MN =8units NO = 6 units MO = 10 units
</span><span>XY = 6.32 units YZ = 6.32 units XZ = 8.94 units
</span>JK = 4.47 units KL = 4.47 units JL = 6 units
1 The
right answer is the letter b) triangle ABC and Triangle MNO are Congruent
<span>triangles
ABC and MNO are triangles that have the same lengths of its three sides.
</span>2 The answer is the letter c)
rotation
There
is a rotation of
90º about ABC and MNO the origin is B=N
B=N
C----------O
A----------M
