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DedPeter [7]
2 years ago
4

Determine the total time that must elapse until only 1/16 of an original sample of th-234 remains unchanged.

Chemistry
1 answer:
viktelen [127]2 years ago
4 0
Answer is: the total time that must elapse until only 1/16 of an original sample of Th-234 remains unchanged is 96.4 days.

Half-life of thorium-234 isotope is 24.1 days.
After first half-life there is 1/2 of an original  sample.
After second half-life there is 1/4 of an original sample.
After third half-life there is 1/8 of an original sample.
After fourth half-life there is 1/16 of an original  sample, so after four half lifes:
 4 · 24.1 days = 96.4 days.
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A generic gas, x, is placed in a sealed glass jar and decomposes to form gaseous y and solid z. 2x(g)↽−−⇀y(g)+z(s) how are these
Aleksandr [31]
Answer: the equilibrium will be displaced to the right leading an increase on the quantities of y(g) and z(s).

Justification:

According to the rules of equilibrium, based on Le Chatellier's priciple, any change in a system in equilibrium will be tried to be compensated to restablish the equilibrium

The higher the amount, and so the concentration, of X(g), the more will the forward reaction proceed leading to an increase on the concentration of the products y(g) and z (s). Look that that will also be accompanied by a decreasing on the pressure, since 2 molecules of the gas X(g) are converted into 1 molecule of the gas y(g).
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2 years ago
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How many moles of calcium chloride (CaCl2) are needed to react completely with 6.2 moles of silver nitrate (AgNO3)? 2AgNO3 + CaC
nexus9112 [7]

Here we have to choose the right option which tells the moles of CaCl₂ will react with 6.2 moles of AgNO₃ in the reaction

2AgNO₃ + CaCl₂→ 2AgCl + Ca(NO₃)₂

6.2 moles of silver nitrate (AgNO₃) will react with B. 3.1 moles of calcium chloride (CaCl₂).

From the reaction: 2AgNO₃ + CaCl₂→ 2AgCl + Ca(NO₃)₂

Thus 2 moles of AgNO₃ reacts with 1 mole of CaCl₂

Henceforth, 6.2 moles of AgNO₃ reacts with \frac{6.2}{2} = 3.1 moles of CaCl₂.

1 mole of CaCl₂ reacts with 2 moles of AgNO₃. Thus-

A. 2.2 moles of CaCl₂ will react with 2.2×2 = 4.4 moles of AgNO₃.

C. 6.2 moles of CaCl₂ will reacts with 6.2×2 = 12.4 moles of AgNO₃.

D. 12.4 moles of CaCl₂ will reacts with 12.4 × 2 = 24.8 moles of AgNO₃

Thus the right answer is 6.2 moles of AgNO₃ will react with 3.1 moles of CaCl₂.

6 0
2 years ago
A cylinder contains 4.0 g of nitrogen gas. A piston compresses the gas to half its initial volume. Afterward, by what factor has
notka56 [123]

Answer:

The mass density will be doubled

Explanation:

  • Density is given by dividing the mass of a substance by its volume.
  • An increase in mass causes an increase in density and vice versa, while a  decrease in volume causes an increase in density and volume.
  • Therefore, when the volume is halved, then the density will be doubled if the mass is kept constant.
  • This has no effect on the number of moles as the mass is constant.
8 0
2 years ago
A chemical reaction is done in the setup shown , resulting in a change of mass. What will happen if the same reaction is done in
irina1246 [14]
<h2>Answer:</h2>

The mass of the system will remain the same if there is no conversion of mass to energy in the reaction.

<h3>Explanation:</h3>
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  • <u><em>Law of conservation of the mass: In simple words, it is described as the mass of a closed system can never be changed, it may transfer from one form to another or change into energy.</em></u>
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5 0
2 years ago
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How many molecules are in 3.6 grams of NaCl?
raketka [301]

Answer:

\boxed{\text{None}}

Explanation:

There are no molecules in NaCl, because it consists only of ions.

However, we can calculate the number of formula units (FU) of NaCl.

Step 1. Calculate the moles of NaCl

\text{No. of moles}=\text{3.6 g NaCl}\times \dfrac{\text{1 mol NaCl}}{\text{63.54 g NaCl}} = \text{0.0567 mol NaCl}

Step 2. Convert moles to formula units

\text{FU} = \text{0.0567 mol NaCl} \times \dfrac{6.022 \times 10^{23}\text{ FU NaCl}}{\text{1 mol NaCl}}\\\\= 3.4 \times 10^{22} \text{ FU NaCl}

There are \boxed{3.4 \times 10^{22} \text{ FU NaCl}} in 3.6 g of NaCl.

6 0
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