Copper (ii) bromide and lead (ii) acetate express your answer as a chemical equation. identify all of the phases in your answer.
2 answers:
Explanation:
Aqueous solution of copper (II) bromide when reacts with aqueous solution of lead (II) acetate then it results in the formation of an insoluble solid of lead bromide and an aqueous solution of copper acetate.
The chemical reaction equation will be as follows.
This reaction is basically a double displacement reaction.
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Answer:
1.82 g is the maximum mass of CuS.
Explanation:
Considering:
Or,
Given :
<u>For :
</u>
Molarity = 0.500 M
Volume = 38.0 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 38.0×10⁻³ L
Thus, moles of :
<u>Moles of = 0.019 moles
</u>
<u>For :
</u>
Molarity = 0.600 M
Volume = 42.0 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 42.0×10⁻³ L
Thus, moles of :
<u>Moles of = 0.0252 moles
</u>
According to the given reaction:
1 mole of reacts with 1 mole of
So,
0.019 mole of reacts with 0.019 mole of
Moles of = 0.019 mole
Available moles of = 0.0252 mole
<u>Limiting reagent is the one which is present in small amount. Thus, is limiting reagent.</u>
The formation of the product is governed by the limiting reagent. So,
1 mole of gives 1 mole of
0.019 mole of gives 0.019 mole of
Moles of formed = 0.019 moles
Molar mass of = 95.611 g/mol
Mass of = Moles × Molar mass = 0.019 × 95.611 g = 1.82 g
<u>1.82 g is the maximum mass of CuS.</u>
<u>Answer:</u>
<em>The specific heat capacity for gold in 105 joules which are required to heat 30.0 grams of gold is 0.129 J/(g℃)</em>
<u>Explanation:</u>
We make use of the formula
where
∆T = final T - initial T
= 54.9℃ - 27.7℃ = 27.2℃
Q is the heat energy in Joules = 105J
c is the specific heat capacity = ?
m is the mass of Gold = 30.0g
Rearranging the formula
So,
c = 0.129 J/(g℃)
(Answer)