Answer:
0.290 atm is the pressure of the system after 7.7min
Explanation:
The general first-order rate constant is:
ln [A] = -kt + ln [A]₀
<em>Where [A] is concentration of A in time t,</em>
<em>K is rate constant, 3.2x10⁻⁴s⁻¹</em>
<em>[A]₀ is initial concentration = 0.336atm.</em>
<em />
7.7 min are:
7.7min * (60s / 1min) = 462s
Solving:
ln [A] = -kt + ln [A]₀
ln [A] = -<em>3.2x10⁻⁴s⁻¹*462s</em> + ln [0.336atm]
ln [A] = -1.238
[A] =
<h3>0.290 atm is the pressure of the system after 7.7min</h3>
<em />
Reactions of Ethyl-3-pentenoate with all given reagents are given below.
Reaction with H₂ / Pd:
The non-polar double bond present in Ethyl-3-pentenoate is reduced to saturated chain. This reagent can not reduce the carbonyl group.
Reaction with NaBH₄: Sodium Borohydride is a weak reducing agent at compared to LiAlH₄. It can only reduce aldehydes and Ketones to corresponding alcohols.
Reaction with LiAlH₄: Lithium Aluminium hydride is a strong reducing agent. It can reduce all types of carbonyl compounds to corresponding alcohols, But, it can not reduce non-polar double bonds like alkenes and alkynes.
Result: The correct answer is
Option-A (Highlighted RED below).
Answer:
Adding a solution containing an anion that forms an insoluble salt with only one of the metal ions.
Explanation:
The student have in solution Ag⁺ and Cu²⁺ ions but he just want to analyze the silver, that means he need to separate ions.
Centrifuging the solution to isolate the heavier ions <em>FALSE </em>Centrifugation allows the separation of a suspension but Ag⁺ and Cu²⁺ are both soluble in water.
Adding enough base solution to bring the pH up to 7.0 <em>FALSE </em>At pH = 7,0 these ions are soluble in water and its separation will not be possible.
Adding a solution containing an anion that forms an insoluble salt with only one of the metal ions <em>TRUE </em>For example, the addition of Cl⁻ will precipitate the Ag⁺ as AgCl(s) allowing its separation.
Evaporating the solution to recover the dissolved nitrates. <em>FALSE</em> . Thus, you will obtain the nitrates of these ions but will be mixed doing impossible its separation.
I hope it helps!